Question

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A uniform meter stick with a mass of 151 grams is supported horizontally by two ideal strings One string is attached at x=0 cm. The other string is attached at x = 90.0 cm An additional mass of 249 grams is balanced on the stick at x = 30.0 cm. Calculate the tension in the left string. Submit Answer Tries 0/10 Calculate the tension in the right string. Submit Answer Incorrect. Tries 1/10 Previous Tries

Answer 1

here,

mass of uniform stick , m1 = 151g = 0.151 kg

additional mass , m2 = 249 g = 0.249 kg

let the tension in the left string be Tl

taking moment of force about the right End

m2 * g * ( 90 - 30) + m1 * g * ( 90/2) + Tl * 90 = 0

0.249 * 9.81 * ( 90 - 30) + 0.151 * 9.81 * ( 90/2) + Tl * 90 = 0

solving for Tl

Tl = 0.91 N

let the tension in the right side string be Tr

equating the forces vertically

Tl +Tr = (m1 + m2) * g

0.91 + Tr = ( 0.151 + 0.249) * 9.81

solving for Tr

Tr = 4.31 N

the tension in the right string is 4.31 N