Question

please help! i keep being given the wrong answer

A beam of white light goes from air into water at an incident angle of 61.0. At what angles are the red (660 nm) and blue (470 nm) parts of the answer to at least one decimal place.) red 41.07 blue 40.686

Answer 1

Solution: Given that: A beam of white light goes fron, air into water at an incident angle of =° 61.0° We know that according Shell's law of soepraetim. too ni sina, = he sing where , n = index of refraction of medium I ng - Index of refraction of medium 2 o = is the angle between say and puspendicellas is medium , O2 = angle blu ray and perpendicular is medium as we knows first medium is air so refraction index of n = 100 Rearrange the expression for the angle between day and perpendicular of red light In, sino пр. refraction 1:33 with Reference to table the value of the of red wavelength & Medium warteo then, ni = 1:00 'np = 1:33), 0, = 6100 :: Op = sin! (0.6576)

[Og = 41569 in the angle Medium 2 between roy and perpendiculos IS 410° ray Reverrange the expresion for the angle blu and peopenclicular for blue light Op = sin" ( min ) the value of the refraction of blue wavelength of the medium water. = 1.338 ng m, = 1.00 nB = 1.338 0,= 61.00 :-1 (x sin 66007 Oe = sin1.338 sin' (0.630129472) TOO = 39.00] Hence , the angle of refraction for red is [41.10 and for blue part is 39:00 part