A proton enters a region of constant magnetic field, perpendicular to the fie and after being...
A proton enters a region of constant magnetic field, perpendicular to the field and after being accelerated from rest by an electric field through an electrical potential difference of 470 V. Determine the magnitude of the magnetic field, if the proton travels in a circular path with a radius of 22 cm. 1.42e-3 How can you determine the speed at which the proton enters the region of constant magnetic field? What force provides the centripetal force that causes the proton...
As shown in the figure, an electron is fired with a speed of 3.73 x 10 m/s through a hole in one of the two parallel plates and into the region between the plates separated by a distance of 0.24 m. There is a magnetic field in the region between the plates and, as shown, it is directed into the plane of the page (perpendicular to the velocity of the electron). Determine the magnitude of the magnetic field so that...
A proton enters a region of constant magnetic field, perpendioular to the field and after being accelerated from rest by an electric fneld through an electrical potential difference of 360 V. Determine the magnitude of the magnetic field, if the proton travels in a circular path with radius of 30 cm. Addiional Materials
A particle with the same mass and charge as a proton enters a region where the magnetic field has a magnitude of 4000 G. The particle moves in a circular path of radius of 20 cm. Determine the speed and period of the particle in the magnetic field.
I . A particle with the same mass and load as a proton enters a region where the magnetic field has a magnitude of 4000 G. The particle moves in a circular radius trajectory of 20 cm. Determine the speed and period of the particle in the magnetic field II. A proton in a particle accelerator has a speed of 5.0 x 10^6 m / s. The proton is found with a magnetic field whose magnitude is 0.40 T and...
3. (a) Show that when a particle with mass m and charge q enters a magnetic field having its velocity v perpendicular to the direction of the magnetic field B, it will perform a mv circular path of radius R- qB (b) Using the previous result find an expression for the period T of the circular motion. (c) A charged particle moves into a region of uniform magnetic field, goes through half a circle and then exits that region, as...
1. An electron enters a uniform magnetic field of 2.5 mT with a velocity perpendicular to the direction of the field. At what speed must the electron enter the region in order to traverse a circular path with a radius of 2.5 cm?
In a cloud chamber experiment, a proton enters a uniform 0.340 T magnetic field directed perpendicular to its motion. You measure the proton's path on a photograph and find that it follows a circular arc of radius 6.30 cm .
8. A proton enters perpendicular to a magnetic field at 4.50 x 10 m/s that causes it to move in a circular path, due to a magnetic force of 1.85 x 10' N. When the proton is traveling in a circle it produces a current 1.05 x 10- A. What is the strength of the magnetic field? What is the radius of the circle? What is the torque on the proton? (16 pts)
An alpha-particle has a charge of +2e and a mass of 6.64 * 10^-27 kg. It is accelerated from rest through a potential difference that has a value of 1.10 * 10^6 V and then enters a uniform magnetic field whose magnitude is 2.80 T. The alpha-particle moves perpendicular to the magnetic field at all times. What is the speed of the alpha-particle What is the magnitude of the magnetic force on it What is the radius of its circular...