Question

Problem 4.82 The variable resistor in the circuit in (Figure 1) is adjusted for maximum power transfer to Ro. Suppose that R = 5 kl. Resistors (5% tolerance) [12] 10 100 1.0 k 10 k 100 k 1.0 M 120 1.2 k 12 k 120 k 15 150 1.5 k 15 k 150 k 1.5 M 180 1.8 k 18 k 180 k 22 220 2.2 k 22 k 220 k 2.2 M 270 2.7 k 27 k 270 k 33 330 3.3 k 33 k 330 k 3.3 M 390 3.9 k 39 k 390 k 47 470 4.7 k 47 k 470 k 4.7 M 560 5.6 k 56 k 560 k Figure 1 of 1 2.4 kΩ 1.6 k12 + 60 V 4.8 k 15 mA {R 1.8 k 2

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Answer 1

lickr 2.4kR ww Gov Disma Ro 4.8ks www 1.8kr from source toons form methad we can make the Gov Source a Current source 60 I ok 25 mA 2.4k libka Disma Иm A 2.40 4.842 Adding the sources 25mA -15mA ton MA. 2460 // 4iske 2.4 x 4.8 2.4+ 4.8 1.6kR 1.6k 1 1.6k m toma 1.8k

again by Source toonstoxmotion. V-IXR= som x lifk = 16v 1.6k a 1'662 R fo R-ser 16v 1.8kr. Roth. Rth = Llibketliokset 1.8k a)//ske (SKR) 11 ruse a Vth By rodaje dision Virasa) 8 r. Rth=2.5kr D + Vinasu

Port A. for maximum Power flow across Ro- Rth= 2.5kr Roc 2.50ks. Post B. 8 x 8 Pmax 6.4 mw. - 4 Rth 4x2.5k Post is lable resistor Closest 2.7 kr R (table) 2.TR. Port D. 1 2.5k a 1 H 2.7k e Ro ov 8 v 1.538 m A. 2.sk ta-the 12 Ron (11538m)? x 12.7) = 6.3905 mw.