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We are interested in the number of times a teenager must be reminded to do his or her chores each week. A survey of 40 mother
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Answer #1

We find the missing value of P (x) for x = 2

Consider P(x) for x = 2 is k

Sum of all probabilities is always 1

\sum P(x) = 1

2 14 4 + + - + +E+ 40 1 40 40 40 40

c+ 2+5+14+7+4 40 - 1

k + \frac{32}{40}= 1

k = 1 - \frac{32}{40}

k = \frac{40- 32}{40}

k = \frac{8}{40}

P(X) for x = 2 is

\frac{8}{40}

The formula of expected value

Expected \ value = \sum x*P(x)

x P(X) x*P(x)
0 \frac{2}{40} 0*\frac{2}{40}= {\color{Purple} 0}
1 \frac{5}{40} 1*\frac{5}{40}= {\color{Purple}\frac{5}{40} }
2 \frac{8}{40} 2*\frac{8}{40}= {\color{Purple}\frac{16}{40} }
3 \frac{14}{40} 3*\frac{14}{40}= {\color{Purple}\frac{42}{40} }
4 \frac{7}{40} 4*\frac{7}{40}= {\color{Purple}\frac{28}{40} }
5 \frac{4}{40} 5*\frac{4}{40}= {\color{Purple}\frac{20}{40} }

expected \ value = \sum x*P(x) = 0+ \frac{5}{40}+ \frac{16}{40}+ \frac{42}{40}+ \frac{28}{40}+ \frac{20}{40}

expected \ value = \sum x*P(x) = \frac{0+5+16+42+28+20}{40}

expected \ value = \sum x*P(x) = \frac{111}{40} = 2.775

Round the expected value up to 2 decimal

expected \ value = \sum x*P(x) ={\color{Purple} 2.78}

Final answer:-

The correct choice is (a)

Expected number of times a teenager is reminded to do his or her chores = 2.78

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