184.55 g of aluminum sulfide (50.2 g/mol) and 134.05 g of water (18.0 g/mol) react until all the limiting reactant is used. What is the mass of H2S (34.1 g/mol) that can be produced from these reactants?
1 Al2S3 + 3 H2O -----> 2 Al(OH)3 + 3 H2S
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184.55 g of aluminum sulfide (50.2 g/mol) and 134.05 g of water (18.0 g/mol) react until...
Consider the reaction below Al2S3(s) + H2O(l) → Al(OH)3(s) + H2S(g) If 15.0g of aluminum sulfide and 10.0g of water are allowed to react as above, and assuming a complete reaction a. by calculation, find out which is the limiting reagent. b. calculate the maximum mass of H2S which can be formed from these reagents. c. calculate the mass of excess reagent remaining after the reaction is complete.
Calculate the maximum numbers of moles and grams of H2S that can form when 153.0 g of aluminum sulfide reacts with 143.0 g of water: Al2S3 + H2O → Al(OH)3 + H2S [unbalanced] ______ mol H2S ______ g H2S What mass of the excess reactant remains? ______ g excess reactant
please help with all questions! Fall 2109 CHE 151-01 Exam 2 Chapter 4-6 Question 5 Question 6 (21 Points) Al2S3 + H2O - Al(OH)3 + H2S Suppose 316.0 g aluminum sulfide reacts with 0.493 kg of water. a) Write the balanced equation (2 Points) b) What % of Al(OH)3 is Al by mass? (2 Points) c) Identify the limiting and excess reagents (2Points) d) Calculate the number of moles and the mass in (g) after the reaction is complete for:...
Determine the theoretical yield of H2S (in grams) if 76.0 g Al2S3 and 53.0 g H2O are reacted according to the following balanced reaction. Identify the limiting reactant. Al2S3 (s) + 6H2O (l) ---> 2 Al(OH)3 (s) + 3 H2S (g)
Consider the reaction of sodium sulfide with oxygen and water. 2Na2S (aq) + 2O2 (g) + H2O (l) -----> Na2S2O3 (aq) + 2NaOH (aq) Determine the limiting reactant in a mixture containing 195 g of Na2S, 67.2 g of O2, and 26.8 g of H2O. Calculate the maximum mass (in grams) of sodium thiosulfate, Na2S2O3, that can be produced in the reaction. Also determine if the limiting reactant is: Na2S, H2O, or O2
Make UP lef Check my work Be sure to answer all parts. Calculate the maximum numbers of moles and grams of H2S that can form when 127.3 g of sulfide reacts with 143.0 g of water: Al2Sg + H2O ? Al(OH)3 + H2S [unbalanced] mol H2S g H2S What mass of the excess reactant remains? g excess reactant
A mixture of 82.5 g of aluminum and 117.6 g of oxygen is allowed to react. Identify the limiting reactant and determine the mass of the excess reactant present in the vessel when the reaction is complete Balanced equation: 4 Al + 3 O2 ===> 2 Al2O3
Al253 (s) + 6H20 (0) --> 2Al(OH)3 (aq) + 3H2S (8) How many grams of H2S will be produced from 30.0 g of Al S3 and 20.0 g of H2O? Which of these reactants is the limiting reactant?
hi! can you please help me figure out part C and D please? I re-did my work on part A, but don't know how to do part C and D. Thank you so much :) H23 - 1.00794 (2) + 32.066 = 34.08188 Alz S3 > 26.981538 (2) + 32.066(3) = 150.161076 PART II: PROBLEMS: Give a complete solution to each problem. SHOW YOUR WORK! Follow proper procedures concerning units and sig figs. Point values given. 6. Consider this unbalanced...
32. Aluminum hydroxide reacts with carbon dioxide as follows: 2 Al(OH)3 (aq) + 3 CO2 (g) → Alz(CO3) (8) + 3 H20 Which is the limiting reactant when 3.0 mol Al(OH)3 and 4.0 mol CO2 are allowed to react? a) Al(OH)3 b) CO2 c) H20 d ) Alz(CO3)3 33. For the above reaction in problem 32, Which is the limiting reactant when 3.0 g of Al(OH)3 and 4.0 g of CO2 are allowed to react? a) Al(OH)3 b) CO2 c)...