Homework Answers
P-value for the given test at 0.05 level of significance is 0.128.
Since p-value is greater than 0.05, we accept the null hypothesis at 5% level of significance.
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Given a simple random sample size of 18, test the null hypothesis Ho: u = 10.5...
Alejandra is using a one-sample t-test to test the null hypothesis Ho: u = 10.0 against...
Alejandra is using a one-sample t-test to test the null hypothesis Ho: u = 10.0 against the alternative H1: 4 < 10.0 using a simple random sample of size n = 10. She requires her results to be statistically significant at level a = 0.10. Determine the maximum value of t that will reject this null hypothesis. You may find this table of t-critical values useful. If you are using software, you may find this catalog of software guides useful....
9 Test the null hypothesis Ho : u = 3.0against the alternative hypothesis HA: U < 3.0 , based on a random sample of 2...
9
Test the null hypothesis Ho : u = 3.0against the alternative hypothesis HA: U < 3.0 , based on a random sample of 25 observations drawn from a normally distributed population with ū = 2.8 and o = 0.70. a) What is the value of the test statistic? Round your response to at least 3 decimal places. Number b) What is the appropriate p-value? Round your response to at least 3 decimal places. Number c) Is the null hypothesis...
Hypothesis test results: u : Mean of variable Ho: u = 2.3 Ha:u>2.3 Variable Sample Mean...
Hypothesis test results: u : Mean of variable Ho: u = 2.3 Ha:u>2.3 Variable Sample Mean Std. Err. DF Length 2.58937 0.205288 399 T-Stat 1.409581 P-value 0.0797 A data set includes data from 400 random tornadoes. The display from technology available below results from using the tornado lengths (miles) to test the claim that the mean tornado length is greater than 2.3 miles. Use a 0.05 significance level. Identify the null and alternative hypotheses, test statistic, P-value, and state the...
To test Ho: u = 20 versus Hy: u<20, a simple random sample of size n= 16 is obtained from a population that is known...
To test Ho: u = 20 versus Hy: u<20, a simple random sample of size n= 16 is obtained from a population that is known to be normally distributed. Answer parts (a)-(d). Click here to view the t-Distribution Area in Right Tail. (a) If x = 18.1 and s = 4.1, compute the test statistic. t (Round to two decimal places as needed.) (b) Draw a t-distribution with the area that represents the P-value shaded. Which of the following graphs...
For the given null (Ho) and alternative (H1) hypotheses, compute the maximum value of z that...
For the given null (Ho) and alternative (H1) hypotheses, compute the maximum value of z that leads to a rejection of the null for a one-sample left-tailed z-test for a mean with a significance level of a = 0.05. Họ: A = 15 H1: 4 < 15 Use software to find the value of z to at least three decimal places. You may find one of these software manuals useful. z =
How do you solve for the P-value? In a hypothesis test with hypotheses Ho : j...
How do you solve for the P-value?
In a hypothesis test with hypotheses Ho : j < 54 and H1 :u > 54, a random sample of 24 elements selected from the population produced a mean of 59.0 and a standard deviation of 14.0. The test is to be made at the 2.5% significance level. Assume the population is normally distributed. What is the critical value of t? 1.96 02.064 • 2.069 -2.069 What is the value of the test...
The one-sample -statistic for a test of Ho: u = 42 versus H1: /i < 42 based on n = 15 observations has the value 1=1...
The one-sample -statistic for a test of Ho: u = 42 versus H1: /i < 42 based on n = 15 observations has the value 1=1.757, where Ho and Hiare the null and alternative hypotheses, respectively. The sample size is denoted by n Use this r-table to determine which two P-values bracket the P-value of the test. Report your answers in decimal form as listed in the 1-table K P-value of the test <
For the given null (H) and alternative (H1) hypotheses, compute the maximum value of z that...
For the given null (H) and alternative (H1) hypotheses, compute the maximum value of z that leads to a rejection of the null for a one-sample left-tailed z-test for a mean with a significance level of a = 0.10. Ho: u = 15 H:< 15 Use software to find the value of z to at least three decimal places. You may find one of these software manuals useful. Z = -
In a test of the hypothesis Ho: u = 59 versus Ha: u>59, a sample of...
In a test of the hypothesis Ho: u = 59 versus Ha: u>59, a sample of n = 100 observations possessed mean x = 58.5 and standard deviation s = 3.8. Find and interpret the p-value for this test. The p-value for this test is (Round to three decimal places as needed.)
To test Ho: u = 105 versus Hy: # 105 a simple random sample of size...
To test Ho: u = 105 versus Hy: # 105 a simple random sample of size n= 35 is obtained. Complete parts a through e below. Click here to view the t-Distribution Area in Right Tail. (a) Does the population have to be normally distributed to test this hypothesis? Why? O A. No, because the test two-tailed OB. Yes, because n 2 30. OC. No, because n 2 30. OD. Yes, because the sample random (b) If x= 101.9 and...
Alejandra is using a one-sample t-test to test the null hypothesis Ho: u = 10.0 against the alternative H1: 4 < 10.0 using a simple random sample of size n = 10. She requires her results to be statistically significant at level a = 0.10. Determine the maximum value of t that will reject this null hypothesis. You may find this table of t-critical values useful. If you are using software, you may find this catalog of software guides useful....
9
Test the null hypothesis Ho : u = 3.0against the alternative hypothesis HA: U < 3.0 , based on a random sample of 25 observations drawn from a normally distributed population with ū = 2.8 and o = 0.70. a) What is the value of the test statistic? Round your response to at least 3 decimal places. Number b) What is the appropriate p-value? Round your response to at least 3 decimal places. Number c) Is the null hypothesis...
Hypothesis test results: u : Mean of variable Ho: u = 2.3 Ha:u>2.3 Variable Sample Mean Std. Err. DF Length 2.58937 0.205288 399 T-Stat 1.409581 P-value 0.0797 A data set includes data from 400 random tornadoes. The display from technology available below results from using the tornado lengths (miles) to test the claim that the mean tornado length is greater than 2.3 miles. Use a 0.05 significance level. Identify the null and alternative hypotheses, test statistic, P-value, and state the...
To test Ho: u = 20 versus Hy: u<20, a simple random sample of size n= 16 is obtained from a population that is known to be normally distributed. Answer parts (a)-(d). Click here to view the t-Distribution Area in Right Tail. (a) If x = 18.1 and s = 4.1, compute the test statistic. t (Round to two decimal places as needed.) (b) Draw a t-distribution with the area that represents the P-value shaded. Which of the following graphs...
For the given null (Ho) and alternative (H1) hypotheses, compute the maximum value of z that leads to a rejection of the null for a one-sample left-tailed z-test for a mean with a significance level of a = 0.05. Họ: A = 15 H1: 4 < 15 Use software to find the value of z to at least three decimal places. You may find one of these software manuals useful. z =
How do you solve for the P-value?
In a hypothesis test with hypotheses Ho : j < 54 and H1 :u > 54, a random sample of 24 elements selected from the population produced a mean of 59.0 and a standard deviation of 14.0. The test is to be made at the 2.5% significance level. Assume the population is normally distributed. What is the critical value of t? 1.96 02.064 • 2.069 -2.069 What is the value of the test...
The one-sample -statistic for a test of Ho: u = 42 versus H1: /i < 42 based on n = 15 observations has the value 1=1.757, where Ho and Hiare the null and alternative hypotheses, respectively. The sample size is denoted by n Use this r-table to determine which two P-values bracket the P-value of the test. Report your answers in decimal form as listed in the 1-table K P-value of the test <
For the given null (H) and alternative (H1) hypotheses, compute the maximum value of z that leads to a rejection of the null for a one-sample left-tailed z-test for a mean with a significance level of a = 0.10. Ho: u = 15 H:< 15 Use software to find the value of z to at least three decimal places. You may find one of these software manuals useful. Z = -
In a test of the hypothesis Ho: u = 59 versus Ha: u>59, a sample of n = 100 observations possessed mean x = 58.5 and standard deviation s = 3.8. Find and interpret the p-value for this test. The p-value for this test is (Round to three decimal places as needed.)
To test Ho: u = 105 versus Hy: # 105 a simple random sample of size n= 35 is obtained. Complete parts a through e below. Click here to view the t-Distribution Area in Right Tail. (a) Does the population have to be normally distributed to test this hypothesis? Why? O A. No, because the test two-tailed OB. Yes, because n 2 30. OC. No, because n 2 30. OD. Yes, because the sample random (b) If x= 101.9 and...
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