The start codon is AUG. Methionine is the only amino acid specified by just one codon,
The sequence of the mRNA is: AGAGAUGUUUAAACCCUGACAGCA A
_______ MEKP
ANSWER :
If the sequence of mRNA molecule is AGAGAUGUUUAAACCCUGACAGCA then the corresponding sequence of amino acids in the encoded polypeptide chain would be as follows :-
Methionine (encoded by start codon AUG) - phenylalanine - Lysine - Proline
Further, nucleotide sequence of mRNA would not be coded to amino acids because it ends by the UGA (stop or termination codon).
Use the codon sequence below to translate the following mRNA sequence (remember to start with the start codon - AUG - codes for methionine): mRNA sequence - AUGUAUAAGUAA [ Choose ] methionine lysine Stop tyrosine 1st codon 2nd codon 3rd codon 4th codon 2. Choose terms that are associated with eukaryotic transcription control. Group of answer choices operators transciption factors repressors enhancers
C++: Translating mRNA sequence help Homework Description Codon 1 You are working in a bioinformatics lab studying messenger RNA (mRNA) sequences. mRNA is a sequence of the nucleotide bases (Adenine, Cytosine, Guanine, and Uracil) that conveys information stored in DNA to Ribosomes for translation into proteins. The bases in the sequences are denoted by the first letters of the nucleotide bases (e.g. A, C, G, and U). A sequence of mRNA is made up of hundres to thousands of nucleotide...
Below is the mRNA sequence for the mRNA transcript used as the blueprint to make a specific protein. Write the DNA leading strain sequence, complimentary lagging stain sequence, and the protein with the amino acid sequence. Use the Codon Table provided. The mRNA transcript is provided for you. Leading strain : 5’ Lagging strain: 3’ mRNA transcript:5’ AUG UAC UAG GGC CCA AUU GAA ACG GGG ACC CCA GCC UGA3’ protein amino acid:
Indicate the amino acid sequence of the protein encoded by the following mRNA molecule. Use the genetic code table and assume that the very first “AUG” the ribosome encounters will serve as the start codon. 5’-AAUUCAUGCCCAAAUUUGGGGCACGAAGCUUCUUAGGCUAGUCCUAAAAAA-3’
1) The 5'-end of an mRNA has the sequence: ...GUCCCAUUGAUGCAUGAAUCAUAUGGCAGAGCCCGCUGG... What is the nucleotide sequence of the DNA template strand from which it was transcribed? 2) If this mRNA is translated beginning with the first AUG codon in its sequence, what is the N-terminal amino acid sequence of the protein that it encodes?
BONUS (10 points, 2 points each): Given below is a sequence of mRNA that is transcribed from a structural and mRNA: AUG CGC GOA UCC CCC ACC AGA ACG GAX UGA-3 G-C 1. Using the codon chart provided below, write down the predicted amino acid sequence of the protein the produced from this mRNA 3-UAC GCG EXU AGG GGG UGG UCU UGC COU 2). Write down the DNA sequence of the structural pene from which this mRNA sequence is transcribed...
help Question 10 If a codon on mRNA IS UGC what will be the anticodon on tRNA and which amino acid will it make? AAA., methionine ACG, cystein UUU, phenylalanine AUG, methionine © UAC, tyrosine
Original DNA & mRNA: DNA template: 3' - GGGTACGGCTCTAAA(300b)TACCCGATCGTA - 5' mRNA: 5' - CCCAUGCCGAGAUUU(300b)AUGGGCUAGCAU - 3' What effect would the following DNA mutation have on the polypeptide synthesized from the gene? DNA template: 3' - GGGTTCGGCTCTAAA(300b)TACCCGATCGTA - 5' mRNA: 5' - CCCAAGCCGAGAUUU(300b)AUGGGCUAGCAU - 3' There will be no effect because the codon still calls for the same amino acid. The polypeptide's synthesis will stop too soon because a stop codon has been introduced too early in the sequence. A...
Question 5 2 pts Given the following mRNA codon sequence, what will be the resulting amino acid sequence after translation? 5'| AUG - GCG-GGU - GCC - UUA - UGA13' sequenci [Select] [Select] Thr Ala [Select] Met lle Tyr Leu [Select] codon table.png
A portion of the template strand of DNA has the following sequence: 5' ATA GCG TTC CAC CGC 3'. Assume the first codon for the peptide begins with the first nucleotide of the portion of mRNA and there are no introns (May not start at AUG). Enter the mRNA and amino acid sequence below