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3. Answer the question below for the following code. module Shift_Register8 (Q, Data_in, Clk, Load, Shift_left,...
Answer the question below for the following code, What does reg (7:0) do? What does always...
Answer the question below for the following code, What does reg (7:0) do? What does always @ (posedge Cik) do? C What causes 2"b01: if (Clk 1) Q<= >> 1 to execute? When it executes, what does it do module Shift_Register (Q, Data_in, Clk, Load, Shift_left, Shift_right); output [ 7:0] Q; reg [7:0] Q, input (7:0) Data_in; input Clk, Load, Shift_left, Shift_right; always @ (posedge Clk) if (Load) Q<Data_in; else case ( { Shift_left, Shift_right)) 2'600: if (Clk - 1)...
How do I create a testbench with the verilog code below? module ganada(Clk, U1, D2, U2,...
How do I create a testbench with the verilog code below? module ganada(Clk, U1, D2, U2, D3, U3, D4, F1, F2, F3, F4, CF, S); input Clk, U1, D2, U2, D3, U3, D4, F1, F2, F3, F4; output [6:0] CF, S; reg [6:0] CF, S; reg [1:0] SS, B, NS; initial begin NS=2'b00; SS=2'b00; end always@(posedge Clk) begin case(NS) 2'b00: CF=7'b1111001; 2'b01: CF=7'b0100100; 2'b10: CF=7'b0110000; 2'b11: CF=7'b0011001; endcase case(SUD) 2'b00: S=7'b1000000; 2'b01: S=7'b1111001; 2'b10: S=7'b0100100; default: S=7'b0000000; endcase if(U1==1 ||...
Given the following verilog code, draw the corresponding state diagram for it. module mysterious (input reset,...
Given the following verilog code, draw the corresponding state diagram for it. module mysterious (input reset, clk, TB, TA, output reg [1:0] LB, LA); reg [1:0] cstate, nstate; parameter S0 = 2'b00; parameter S1 = 2'b01; parameter S2 = 2'b10; parameter S3 = 2'b11; parameter grn = 2'b00; parameter ylw = 2'b01; parameter rd = 2'b10; // state register always @ (posedge clk, posedge reset) begin if (reset) cstate <= S0; else cstate <= nstate; end // next state logic...
Please explain what he verilog code does: module lab7_2_3( input clk, input Enable, input Clear, input...
Please explain what he verilog code does: module lab7_2_3( input clk, input Enable, input Clear, input Load, output [3:0] Q, reg [3:0] count, wire cnt_done ); assign cnt_done = ~| count; assign Q = count; always @(posedge clk) if (Clear) count <= 0; else if (Enable) if (Load | cnt_done) count <= 4'b1010; // decimal 10 else count <= count - 1; Endmodule
(15 pts) 1. Draw a logic diagram for the Verilog code. module Seq_Ckt ( CLK, PR,...
(15 pts) 1. Draw a logic diagram for the Verilog code. module Seq_Ckt ( CLK, PR, sel, Q); input CLK, PR, sel; output reg [2:0] Q; reg [2:0] y; assign Q = y; always @ (posedge PR, posedge CLK) begin if (PR== 1) then y <= 3'b111; else if (sel) begin y[2] <= y[1] ^ y[0]; y[1] <= y[2]; y[1]; end else y[2] <= y[2] ; y[1] <= y[1]; y[0]; y[O] <= y[0] <= end endmodule
Write a testbench for LFShift shift register example module 1f3r input clk, input reset, output a...
Write a testbench for LFShift shift register
example
module 1f3r input clk, input reset, output a ); reg (5:0] shift; wire xor_sum; assign xor_sum = shift[1] ^ shift[4]; // feedback taps always @ (posedge clk) if (reset) shift <= 6'b111111; // initialize LFSR else shift <= { xor_sum, shift [5:1] }; // shift right assign a = shift[0]; // output of LFSR endmodule
I need help writing a test bench for the following Verilog code module CU(IE, WE, WA,...
I need help writing a test bench for the following Verilog code module CU(IE, WE, WA, RAE, RAA, RBE, RBA, ALU, SH, OE, start, clk, reset, Ng5); //nG5 denotes (N>5); input start, clk, reset; output IE, WE, RAE, RBE, OE; output [1:0] WA, RAA, RBA, SH; output [2:0] ALU; input wire Ng5; reg [1:0] state; reg [1:0] nextstate; parameter S0 = 3'b000; parameter S1 = 3'b001;...
Write a testbench for use in Quartus' ModelSim Altera in verilog for the following code of...
Write a testbench for use in Quartus' ModelSim Altera in verilog for the following code of a 4x16 register: module regFile4x16 (input clk, input write, input [2:0] wrAddr, input [15:0] wrData, input [2:0] rdAddrA, output [15:0] rdDataA, input [2:0] rdAddrB, output [15:0] rdDataB); reg [15:0] reg0, reg1, reg2, reg3; assign rdDataA = rdAddrA == 0 ? reg0 : rdAddrA == 1 ? reg1 : rdAddrA == 2 ? reg2 : rdAddrA == 3...
why its 4-to-1 mux behavioral? What does the logic circuit represented by the following Verilog module...
why its 4-to-1 mux behavioral?
What does the logic circuit represented by the following Verilog module do, and what Verilog description style does it use? // My Verilog module #1 module mymodl ( x, d, q) input[1:0] x;input[3:0] d;output q; reg q; wire [1:0] x; wire [3:0] d; always ( x or d) begin case ( x ) 1 : q=d[1]; 2 : g=d[2]; 3 q d[3]; endcase end endmodule
2. What is wrong with the following code (More than one error may exist in each...
2. What is wrong with the following code (More than one error may exist in each seg module mux2_1 (10, 11, S, Y); input 10, 11, S; output Y; lalways @ (posedge s) begin if (S) Y=11; else Y=10; end endmodule module ESM (clk, a, outi, out2): input clk, a: output outi, outi: jalways @ (posedge clk) begin 1 if(state=0) begin if (a) state<=1; end 1 else begin if (-a) states : end end end Jalways @ (state) begin if...
Answer the question below for the following code, What does reg (7:0) do? What does always @ (posedge Cik) do? C What causes 2"b01: if (Clk 1) Q<= >> 1 to execute? When it executes, what does it do module Shift_Register (Q, Data_in, Clk, Load, Shift_left, Shift_right); output [ 7:0] Q; reg [7:0] Q, input (7:0) Data_in; input Clk, Load, Shift_left, Shift_right; always @ (posedge Clk) if (Load) Q<Data_in; else case ( { Shift_left, Shift_right)) 2'600: if (Clk - 1)...
(15 pts) 1. Draw a logic diagram for the Verilog code. module Seq_Ckt ( CLK, PR, sel, Q); input CLK, PR, sel; output reg [2:0] Q; reg [2:0] y; assign Q = y; always @ (posedge PR, posedge CLK) begin if (PR== 1) then y <= 3'b111; else if (sel) begin y[2] <= y[1] ^ y[0]; y[1] <= y[2]; y[1]; end else y[2] <= y[2] ; y[1] <= y[1]; y[0]; y[O] <= y[0] <= end endmodule
Write a testbench for LFShift shift register
example
module 1f3r input clk, input reset, output a ); reg (5:0] shift; wire xor_sum; assign xor_sum = shift[1] ^ shift[4]; // feedback taps always @ (posedge clk) if (reset) shift <= 6'b111111; // initialize LFSR else shift <= { xor_sum, shift [5:1] }; // shift right assign a = shift[0]; // output of LFSR endmodule
why its 4-to-1 mux behavioral?
What does the logic circuit represented by the following Verilog module do, and what Verilog description style does it use? // My Verilog module #1 module mymodl ( x, d, q) input[1:0] x;input[3:0] d;output q; reg q; wire [1:0] x; wire [3:0] d; always ( x or d) begin case ( x ) 1 : q=d[1]; 2 : g=d[2]; 3 q d[3]; endcase end endmodule
2. What is wrong with the following code (More than one error may exist in each seg module mux2_1 (10, 11, S, Y); input 10, 11, S; output Y; lalways @ (posedge s) begin if (S) Y=11; else Y=10; end endmodule module ESM (clk, a, outi, out2): input clk, a: output outi, outi: jalways @ (posedge clk) begin 1 if(state=0) begin if (a) state<=1; end 1 else begin if (-a) states : end end end Jalways @ (state) begin if...
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