Question

Fiber content (In grams per serving) and sugar content (in grams per serving) for 18 high fiber cereals are shown below. Fiber Content 7 11 11 7 9 7 12 12 9 13 11 9 12 7 14 7 99 Sugar Content 11 7 14 13 0 18 9 10 19 0 9 5 11 7 10 17 10 10 (a) Find the median, quartiles, and interquartile range for the fiber content data set. median lower quartile upper quartile interquartile range (b) Find the median, quartiles, and interquartile range for the sugar content data set. median lower quartile upper quartile interquartile range (c) Are there any outliers in the sugar content data set? O Yes, there is one outlier on the high end. Yes, there are two outliers on the high end. Yes, there is one outlier on the low end. Yes, there are two outliers on the low end No, there are no outliers

Answer 1

од To Code us at и Lau, игрн + (а и го quartile we need to arrange toie danta in ascendina ordur. 7, 7, 7, 77, 9,9.9,9,9,11,11,1, 12,12,12,13,14 a Median, is the value of the data set below which and above which 50% value of the data lie. Here, no. of observation = 18 leven) Median & Average of ( 2 m 4 h + 1th) valce a u cate f 10 th ) value z 9 +9 9 at lower a uartile = Below which 25% of data +1 4.75th a = 4th term & 0.75 (5 th terma 4thtern) 7. upper " 7 + 0.75 (2-7) Abone which 25% data lie 3(*#'-) au term

lie upper " ē Above which 25% data 3( -) th term = 3 x 4.75 u 2 14:25 " The 214th term + 0.25(15th 14th) term = 12 + [o 25x112-12)] E ( 2 ,

. upper 10 weer Interquartile range = the range ganetite B a | 12 - 7935. Eh . Like the previous one here again we need to arrange the data in ascending order. 0,0, 5, 7, 7, 9,9,10,10,10,11,11,13,14, 17, 18, 19 here, no. of observation = 18 Ceren). Median ( 2 m + ( / + 1) th value 1/2 Tath 10th ")/2 desa ( 9th to to the 2 lover auartile = (n + 1)th value 3 4.75 sur u. z 4th value + 0.750.5 the 4th) - value = 7+0.75 ( 7–7).

loueer quartile (**)** value ? 4.75 sun z 4th value + 0.756.5th 4th) A value z 7 + 0.75 (7-7) 2 upp er greiartile a 3 (n+1) the value z 3 x =14.25 terit z 14 th valicet 0.25 listerath value 1 3 + 0.25 (14.13) - mer quartile i z z Inter quartile range and a , epaper quartico 13-25 - 7 2 6:25

a In the sugar contrut there is trysing GIRL o two values as o.o. But other than that all the values are lied within the range from 5 to in. We know outliers are some value which cie far away from the usual spread of the data. In this case we can say that, o can be outlier. fo, the ans in D yes, there in two outliers on the love end. @ lower quartile are the median of the lower quarter. Here the first half and second half values of the lower quaviter are all same. so that the minimum & lover auartile are same. The ansi- The bottom quarter of the data values are all доии ш.