Homework Answers
The minimum cost is $825.
| Results | ||||||||||||
| Data | Normal time | 15 | Minimum crash cost to meet project goal | $ 825.00 | ||||||||
| Project goal | 11 | Minimum time | 11 | Project time | 11 | |||||||
| Activity | Normal Time (weeks) | Crash Time (weeks) | Normal Cost | Total Cost with Crashing | Pred 1 | Pred 2 | Pred 3 | Pred 4 | Crash days | Crash cost/day | Crash limit | |
| A | 9 | 7 | $200 | $300 | 2 | 50 | 2 | |||||
| B | 7 | 6 | $800 | $875 | 0 | 75 | 1 | |||||
| C | 5 | 4 | $600 | $675 | 1 | 75 | 1 | |||||
| D | 6 | 4 | $1,100 | $1,300 | A | B | 2 | 100 | 2 | |||
| E | 9 | 6 | $1,200 | $1,875 | C | 2 | 225 | 3 |
Add Answer to:
What is the minimum cost of crashing the following project at Sawaya Robotics by 4 days?...
What is the minimum cost of crashing the following project that Roger Solano manages at Slippery...
What is the minimum cost of crashing the following project that
Roger Solano manages at Slippery Rock University by 4 days?
A)By how many days should each activity be crashed to reduce the
project completion time by 4 days? Fill in the table below.
(Enter your responses as whole numbers.)
B) The total cost of crashing the project by 4 days is $. (Enter
your response as a whole number.)
Normal Crash Time Normal Total Cost Activity Time (days) (days)...
What is the minimum cost of crashing the following project that Roger Solano manages at Slippery...
What is the minimum cost of crashing the following project that Roger Solano manages at Slippery Rock University by 4 days? Normal Crash Time Normal Activity Time (days) (days) Cost $800 $250 $600 $750 $1,200 Uw > A Awarw Total Cost with Crashing Immediate Predecessor(s) $1,100 $600 $650 $1,500 $1,650 OD By how many days should each activity be crashed to reduce the project completion time by 4 days? Fill in the table below. (Enter your responses as whole numbers.)...
What is the minimum cost of crashing the following project that Roger Solano manages at Slippery Rock University by 4 da...
What is the minimum cost of crashing the following project that
Roger Solano manages at Slippery Rock University by 4 days?
Please show work and calculations.
NORMAL CRASH TIME ACTIVITY (DAYS) (DAYS) TIME NORMAL CRASH COST IMMEDIATE COST PREDECESSOR(S) 900 $1,000 B 300 400 C 4 3 500 600 5 3 900 1,200 A 5 1,000 1,600 C LO LO C Ln LLI
NORMAL CRASH TIME ACTIVITY (DAYS) (DAYS) TIME NORMAL CRASH COST IMMEDIATE COST PREDECESSOR(S) 900 $1,000 B 300...
Given below is the crashing data for a project along with other data. The project completion...
Given below is the crashing data for a project along with other data. The project completion time is 20 davs. Determine: (a) the crash slope (i.e crash cost/day) for all activities, (b) the normal total project cost, (c) prioritized the list of activities for crashing from best to worst, (d) the best activity to crash if the project has to be completed in 19 days and alternative critical paths, if any, (e) the earliest time the project can be completed,...
Normal Time Crash Time Normal with Activity (weeks) (weeks) Cost Crashing Immediate Predecessor(s) $1,400 A 3...
Normal Time Crash Time Normal with Activity (weeks) (weeks) Cost Crashing Immediate Predecessor(s) $1,400 A 3 2 $2,050 $2,800 B 2 1 $2,100 1 1 $350 $350 7 $1,400 $1,700 A 6 3 $900 $1,200 $5,000 $2,000 F 2 $4,000 $1,500 C 4 G 2 D, E weeks a) Based on the given information regarding the activities for the project, the project completion date b) To reduce the duration of the project to 10 weeks at the least cost, the...
1) Based on the given information regarding the activities for the project, the project length= ___...
1) Based on the given information regarding the activities for
the project, the project length= ___ weeks.
2) The total cost required for completing this project on normal
time= $____
3) For reducing the duration of the project by one week, the
activity that should be crashed first is activity ___.
4) The cost of the project based on the first activity selected
for crashing will increase by $___.
5) The maximum weeks by which the project can be reduced...
QUESTION 27 What is the cost of crashing the project represented in the table below, by...
QUESTION 27 What is the cost of crashing the project represented in the table below, by 3 days? Immediate Normal Crash Normal Crash Activity Predecessors Time/Days Time/Days Cost Cost А 3 2 $200 $500 B А 3 2 $350 $550 С А 2 1 $300 $250 D B&C 3 $500 $550 E С 2 $500 $900 F D&E . $500 $1,000 NN $150 $450 $550 $2450 $2750 QUESTION 1 According to Michael Porter, the primary activities in a value chain...
Supose Bowman is the first week, it is paid Si50 for crashing it the second week, it is paid $125...
Supose Bowman is the first week, it is paid Si50 for crashing it the second week, it is paid $125: for crashing it the third week, it is paid S100, for crashing it any additional weelks, it is 575 per week. What is the minimum cost schedule and what is the cost of the project based on this schedule 1 9:03 LTE 星期二 下午9:59 编辑 12-24 Bowman Builders manufactures steel storage sneas for commercial use. Joe Bowman, president of Bowman...
Development of Version 20 of a particular accounting software product is being considered by Jose Noguera's...
Development of Version 20 of a particular accounting software product is being considered by Jose Noguera's technology form in Baton Rouge. The activities necessary for the completion of this project are listed in the following table: Immediate Predecessor(s) Activity Normal Time Crash Time Normal (weeks) (weeks) Cost $2,200 $2,200 5750 $2,300 $900 $3.000 $1,600 Total Cost with Crashing $2,850 $3.000 5750 $2.580 $1,200 $4.500 52.200 D.E d) The maximum weeks by which the project can be reduced by crashing =...
The Advanced Tech Company has a project to design an integrated information data base for a major bank. Data for the pr...
The Advanced Tech Company has a project to design an integrated information data base for a major bank. Data for the project are given in the following table. Indirect project costs amount to S150 per day. The company will incur a $100 per day penalty for each day the project lasts beyond day 15. Normal Time Crash Time Crash Cost Immediate Normal Cost ($) Activity (S) (days) (days) Predecessor(s) 6 800 1,200 A 4 6 1,000 2,200 C 600 1...
What is the minimum cost of crashing the following project that
Roger Solano manages at Slippery Rock University by 4 days?
A)By how many days should each activity be crashed to reduce the
project completion time by 4 days? Fill in the table below.
(Enter your responses as whole numbers.)
B) The total cost of crashing the project by 4 days is $. (Enter
your response as a whole number.)
Normal Crash Time Normal Total Cost Activity Time (days) (days)...
What is the minimum cost of crashing the following project that Roger Solano manages at Slippery Rock University by 4 days? Normal Crash Time Normal Activity Time (days) (days) Cost $800 $250 $600 $750 $1,200 Uw > A Awarw Total Cost with Crashing Immediate Predecessor(s) $1,100 $600 $650 $1,500 $1,650 OD By how many days should each activity be crashed to reduce the project completion time by 4 days? Fill in the table below. (Enter your responses as whole numbers.)...
What is the minimum cost of crashing the following project that
Roger Solano manages at Slippery Rock University by 4 days?
Please show work and calculations.
NORMAL CRASH TIME ACTIVITY (DAYS) (DAYS) TIME NORMAL CRASH COST IMMEDIATE COST PREDECESSOR(S) 900 $1,000 B 300 400 C 4 3 500 600 5 3 900 1,200 A 5 1,000 1,600 C LO LO C Ln LLI
NORMAL CRASH TIME ACTIVITY (DAYS) (DAYS) TIME NORMAL CRASH COST IMMEDIATE COST PREDECESSOR(S) 900 $1,000 B 300...
Given below is the crashing data for a project along with other data. The project completion time is 20 davs. Determine: (a) the crash slope (i.e crash cost/day) for all activities, (b) the normal total project cost, (c) prioritized the list of activities for crashing from best to worst, (d) the best activity to crash if the project has to be completed in 19 days and alternative critical paths, if any, (e) the earliest time the project can be completed,...
Normal Time Crash Time Normal with Activity (weeks) (weeks) Cost Crashing Immediate Predecessor(s) $1,400 A 3 2 $2,050 $2,800 B 2 1 $2,100 1 1 $350 $350 7 $1,400 $1,700 A 6 3 $900 $1,200 $5,000 $2,000 F 2 $4,000 $1,500 C 4 G 2 D, E weeks a) Based on the given information regarding the activities for the project, the project completion date b) To reduce the duration of the project to 10 weeks at the least cost, the...
1) Based on the given information regarding the activities for
the project, the project length= ___ weeks.
2) The total cost required for completing this project on normal
time= $____
3) For reducing the duration of the project by one week, the
activity that should be crashed first is activity ___.
4) The cost of the project based on the first activity selected
for crashing will increase by $___.
5) The maximum weeks by which the project can be reduced...
QUESTION 27 What is the cost of crashing the project represented in the table below, by 3 days? Immediate Normal Crash Normal Crash Activity Predecessors Time/Days Time/Days Cost Cost А 3 2 $200 $500 B А 3 2 $350 $550 С А 2 1 $300 $250 D B&C 3 $500 $550 E С 2 $500 $900 F D&E . $500 $1,000 NN $150 $450 $550 $2450 $2750 QUESTION 1 According to Michael Porter, the primary activities in a value chain...
Supose Bowman is the first week, it is paid Si50 for crashing it the second week, it is paid $125: for crashing it the third week, it is paid S100, for crashing it any additional weelks, it is 575 per week. What is the minimum cost schedule and what is the cost of the project based on this schedule 1 9:03 LTE 星期二 下午9:59 编辑 12-24 Bowman Builders manufactures steel storage sneas for commercial use. Joe Bowman, president of Bowman...
Development of Version 20 of a particular accounting software product is being considered by Jose Noguera's technology form in Baton Rouge. The activities necessary for the completion of this project are listed in the following table: Immediate Predecessor(s) Activity Normal Time Crash Time Normal (weeks) (weeks) Cost $2,200 $2,200 5750 $2,300 $900 $3.000 $1,600 Total Cost with Crashing $2,850 $3.000 5750 $2.580 $1,200 $4.500 52.200 D.E d) The maximum weeks by which the project can be reduced by crashing =...
The Advanced Tech Company has a project to design an integrated information data base for a major bank. Data for the project are given in the following table. Indirect project costs amount to S150 per day. The company will incur a $100 per day penalty for each day the project lasts beyond day 15. Normal Time Crash Time Crash Cost Immediate Normal Cost ($) Activity (S) (days) (days) Predecessor(s) 6 800 1,200 A 4 6 1,000 2,200 C 600 1...
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