Question

You are given a circular DNA molecule to analyze that is 3,000bp (3 Kb) long. You proceed to treat the DNA molecule with different cutting enzymes and then you run the individual reactions on a gel. The following gel is produced with each column representing a different reaction (lane). In lane 1 a molecule weight ladder is run. In lane 2, the circular DNA is NOT treated with any enzyme. In lane 3 the DNA is treated with an enzyme that cuts the circular molecule at 1 site only. Lanes 4 and 5 have reactions with enzymes that cut the circular DNA at 2 sites only.

Answer the following questions regarding the results of this gel: a. The uncut DNA in lane 2 travels less than the expected 3Kb. How could the difference between an uncut (circular) from the cut (linear) DNA result in this effect? b. Considering that one cut would result in the single band in lane 3, how would you justify that the enzyme used for lane 4 ONLY cuts the circular molecule at two sites? (Hint- add the number of base pairs for each band in lane 4) c. You already know that the enzyme used in lane 5 will cut the circular DNA in two places. However, unlike lane 4 you only have one fragment. What does this tell about where the DNA is being cut by the enzyme?Lane 1 2 3 4 5 4,000 3,000 2,500 - 2,000 1,500 .. 1,000

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