Question

Hemoglobin is a protein that is found in red blood cells. It binds to oxygen in the lungs and it carries it to tissues and cells throughout the body. Hemoglobin is made of four polypeptide chains, two called “alpha-globins” (a) and two “beta-globins" (B). The B-globin polypeptide is produced in the cells based on the sequence of the HBB gene. The structure of the HBB gene that codes for beta-globin is represented below. The primary transcript is 1606 nucleotides long. This gene contains 3 exons (1... 142, 273...495, 1346... 1606). The start codon (AUG) begins at +51; the stop codon (UAA) begins at +1472. DNA coding strand 5' intron intron Exon 1 Exon 2 Exon 3 3' Primary mRNA transcript 5' 3' Splicing Mature mRNA 5' cap 1-AAAAAAAAAAAA-3' Poly(A) tail 3. On BOTH the diagram of the gene (DNA) AND that of the mature RNA transcript, mark clearly the approximate location of: a) [2 pts) the +1 nucleotide b) [2 pts) the start codon c) [2 pts) the stop codon 4. [3 pts] The protein-coding region of the mature mRNA (including the start codon AUG and the stop codon UAA) is 444 nucleotides long. How many amino acids is the beta-globin polypeptide composed of? Clearly state your answer (claim) and briefly explain your reasoning.

Answer 1

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Dats Poy start codon (+51) inton on 3 7 3: 5 Exon. Exon 2 T tl nucleotide ONA Stop codon (+1472) Start codon (451) AAA 3 mature mRNA 1 rechentiche stop codon codon The beta globin - polypeptide will be composed 146 amino Since containing 3 nucleotides code for one amino aid , 444 nucleotides will code for 444 148 amino acids 3 out 148 codons two codons start and stop not code for any amino so polypeptide will have 146 amino acids acid,