Question

During the course of 24 hours, kidney cells (using special transport proteins) move 384 grams of glucose across their cell membranes from the kidney filtrate to the blood. (In this way valuable glucose is not lost in the urine.) What is the rate of glucose movement across these cell membranes in molecules per second?

Assume the molecular weight of glucose is 180. (One mole of glucose weighs 180 grams.)

1 mole = 6.022 x 10 ²³ molecules

To enter an answer of 1,500, which is the same as 1.5 x 10^3, please type in 1.5E3. To enter 0.0003, which is the same as 3 x 10^-4, please type in 3E-4.

Type your answer into the box below, and do not add units to your answer.

→ A Moving to another question will save this response. < < Question 3 of 10 > >> Question 3 1 points Save Answer During the course of 24 hours, kidney ces using special transport proteins, move 384 grams of glucose across their call membranes from the kidney filtrate to the blood. In this way valuable glucose is not lost in the urine.) What is the rate of glucose movement across these cell membranes in molecules per second? Assure the moicular weight of glucosc is 180. (One mole of glucose weighs 160 gr.) 1 mole = 6.022 x 10 23 molecules To enter an answer of 1.500, which is the same as 1.5x 10 please type in 1.5E3. To enter D.GODS, which is the same as 3 x 10-4, please type in 3E-4. Type your answer into the box below, and do not add units to your answer.

Answer 1

180 grams of Glucose is 1 mole

So, 384 grams of glucose will be (384/180) = 2.13 moles

In 24 hours, 384 grams of glucose is moved, which is equal to 2.13 moles.

Now 1 mole of glucose is 6.022 E23 molecules.

Thus 2.13 moles of glucose will be 2.13 X 6.022 E23 = 1.282 E24 molecules

These number of molecules are moved in 24 hours which is equivalent to 24 x 60 x 60 = 86400 seconds

Thus number of molecules moved per second will be (1.282 E24/86400) = 1.483 E19