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Problem 2.5 Constant Pressure Process Air is compressed from 0.092 m3 to 0.034 m’ at a constant pressure of 1.7 kPaa. Assume

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Solution: V = 0.092 ml , V, = 0.034 m. P = 1.7 kPa. R=3.3145 kPa mi , M.W = 28.964 kg kgndek Cpair = 29.11 kJ 1 kgmolek kgmdNow & Enthalpy change for the process is given by; DH= npat DH = 1.866 X109? yg x 29.11 KJ x (107.87 – 291.97% Hogy TOH= lok]thankyou...please upvote it...

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