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Three membrane receptor proteins bind tightly to a hormone. The free hormone concentrations and their corresponding fractions of hormone binding, Y, are given in the table. [Hormone), nM Protein 1 (Y) Protein 2 (Y) Protein 3 (Y)| 0.20 0.048 0.29 0.17 0.50 0.11 0.50 0.33 1.0 0.20 0.67 0.50 0.50 0.89 0.80 0.71 0.95 0.91 0.83 0.97 0.93 0.99 0.98 0.95 50 Select the K, for hormone binding by protein 2. 0.50 nM 0.99 nM O 0.20 nM 50 nM...
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5. Which of the following parts of the IgG molecule are not involved in binding to an antigen? A) Fab B Fc C) Heavy chain D) Light chain E) Variable domain 6. Three membrane receptor proteins bind tightly to a hormone. Based on the data in the table below, (a) what is the Ka for hormone binding by protein 2? (Include appropriate units.) (b) Which of these proteins binds most Ka for all three proteins tightly to this hormone? (c)...
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The binding of a hormone to three different protein receptors is
measured in separate experiments. The table below shows θ, the
fractional saturation of each receptor, for various hormone
concentrations.
Draw a binding curve that plots the data points for Protein
3. Label the axes of your graph, including the
correct units.
What is the Kd for the interaction of the hormone
with Protein 3?
Draw binding curves for Proteins 1 and
2 on the same graph. Clearly label which...
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1. Based on the data in the table below (a) what is the Kd for hormone binding by Protein1 and Protein ? (b) Which of these proteins binds most tightly to this hormone? Work this problem on a separate piece of graph paper. Y for Protein 2 ormone concentration (nM) Yfor Protein 1 0.17 0.33 0.5 0.8 0.91 0.95 0.98 0.2 .5 5T 4 10 20 50 0.5 0.67 0.89 0.95 0.97 0.99 2. Calculate the fractional saturation of hemoglobin...
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Question Help The following data represent the weights (in
grams) of a random sample of 50 candies.
0.85
0.89
0.82
0.81
0.85
0.87
0.96
0.89
0.91
0.91
0.81
0.86
0.77
0.89
0.85
0.84
0.75
0.84
0.71
0.84
0.91
0.76
0.77
0.95
0.83
0.91
0.88
0.85
0.83
0.78
0.97
0.84
0.75
0.75
0.81
0.76
0.86
0.87
0.86
0.79
0.73
0.95
0.73
0.71
0.83
0.82
0.88
0.93
0.91
0.83
(a) Determine the sample standard deviation weight. =
__?__ gram
(Round to two...
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I need help at the bottom with - (d) Determine the
actual percentage of candies that weigh between 0.7 and 0.98 gram,
inclusive - Thank you!
The following data represent the weights (in grams) of a random
sample of 50 candies.
0.85
0.89
0.82
0.81
0.85
0.87
0.96
0.89
0.91
0.91
0.81
0.86
0.77
0.89
0.85
0.84
0.75
0.84
0.71
0.84
0.91
0.76
0.77
0.95
0.83
0.91
0.88
0.85
0.83
0.78
0.97
0.84
0.75
0.75
0.81
0.76
0.86
0.87
0.86...
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I need help with the final part - (f) Determine the
actual percentage of candies that weigh more than 0.91 gram.
- Thank you!
The following data represent the weights (in grams) of a random
sample of 50 candies.
0.85
0.89
0.82
0.81
0.85
0.87
0.96
0.89
0.91
0.91
0.81
0.86
0.77
0.89
0.85
0.84
0.75
0.84
0.71
0.84
0.91
0.76
0.77
0.95
0.83
0.91
0.88
0.85
0.83
0.78
0.97
0.84
0.75
0.75
0.81
0.76
0.86
0.87
0.86
0.79
0.73...
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4. The following table shows unit costs across different countries: Economy Footwear Textiles Clothing Metal Products Wood Products Rubber Products Plastic Electrical Products Machinery Egypt NA 1.50 0.50 0.85 0.48 1.50 1.23 0.93 India 0.99 1.01 0.49 0.97 0.91 0.88 0.88 0.85 Indonesia 0.85 0.47 0.95 0.55 0.53 0.72 0.64 0.76 Kenya 1.13 1.61 1.17 0.91 1.20 0.61 0.63 0.55 Malaysia 1.08 0.73 1.42 0.83 0.85 0.76 0.92 0.97 Mexico 1.62 0.96 1.20 0.76 0.76 0.96 0.83 0.83 Philippines 1.36...
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At the bottom of each data set, provide a brief narrative
description of the progress of the project and its current status.
There is no need to address every data point. I would prefer that
you look for trends and identify sections of the project as given
in the data. For example, you might say, "In the first half of this
project, everything appears to be on track, but in the last third
the schedule starts to slip."Assume the data...
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Use Table 8.1, a computer, or a calculator to answer the following. Suppose a candidate for public office is favored by only 47% of the voters. If a sample survey randomly selects 2,500 voters, the percentage in the sample who favor the candidate can be thought of as a measurement from a normal curve with a mean of 47% and a standard deviation of 1%. Based on this information, how often (as a %) would such a survey show that...