Question

Introduction NaHCO3 1 mol NOC - MATC03 What mole ratio of NaCl to NaHCO, does the above balanced equation predict? Record your results in the Table below. All values should be to 2 decimal places and include the correct units Tube A Tube 1. Mass of tube + NaHCO3 94.19 2 9-923 Tube C 23-899 24.859 24.812 2. Mass of tube (+ boiling chips) 24.654 3. Mass of NaHCO, 4. Moles of NaHCO, 5. Mass of tube + NaCl 2404189 lass of tube (same as Line 2) 240659 7. Mass of NaCl 24.539 24.539. 24.81929.85 8. Moles of NaCl 9. Ratio: moles of NaCl moles of NaHCO3 Average Ratio for the three test tubes:

Answer 1

Ano- The balanced Chemical equation & - - Nanco + Hill Wall+ CO2 thao In the balanced equation, ratio of Nachto NaHCO3. predicts that amount ¢ Nanca consumed in the reaction is equal to amount of Nall produced Test tube A Test tube B Testtube.c Mas o tube twarcos 24.019 23.92g 3637 | Mass of tubeft boiling (24-65 g 24.81 g 24.859 Had A cos 0-69 8 | 0-09 310 36 3 ftutube + NaHCO3) Holes of Mass 0-69 -0.0076 0:16-0-olly mog 0.89-0-clobal 84 mele J84 84 Nancoz a Nanco, Holecular mass of Nang * Holecular mass of | NAHCO3 = 84 g/mol Mass of tube twice 24.43g 24.53g 24.53g Mass of test tube how (24.659 24.818 24.85g Massd Manage Haus auto.229 0.289 0.289 haltest - tube Fuchinc229 24-25–24.0 = 5233 Holes of Mass of NOVO Holecular, maar 038 0.0048 Oroos moll *Meleculae mass q Noce = 23 g/mol S88 Patie Melus molu MaheG 0.0030 0.008 0. 4OOCATO 0.0076 .0106 0 -0114 Average sectis = 0.540-45+0:48 = 0.4766 70-48 Na may mas + 3x/Polat may * Molecular mou NOHCO is calculated as below- Holar mass of Na = 23 g/mol Holar mass of c, H ando are 12, 1 and 16 g/mol Beespectively. - Molecular mass qNaHCO₃ = Ho Holat masst Molar - Molar + 3x/Molour massi 91 C 190 / - 23+1+2+3x16= 849/mol #Holecular mass - Nad = masse to a Holar Molar mass = 23+3575 = 58.5g/mol * Kindly check your readings because ratto. of moles of Nace and moles of Narcos i for from one. It seems there is experimental errots.