Question

QUESTION 1

The activities summarized in the following table must be preformed by the promoter of a country music concert in Dallas. Immediate Predecessors TA Coco Activity Expected Time (in days) A. Find location B. Hire opening act C. Hire technicians D. Set up radio ads E. Distribute tickets F. Rent sound and lights 2 G. Set up newspaper ads 3 H. Hire security I. Conduct rehearsal B B e B.C | В 1 H

Part1. The total expected project completion time is:

A. 10 days

B. 11 days

C. 15 days

D. none of the above

Part 2. What is the effect of a delay of 1 day in distributing tickets?

A. no impact

B. the project will delay by one day

C. the project will delay by more than one day

D. same as the effect of a delay of 1 day in setting up radio ads

Part 3. What is the critical path for this project (CAN SELECT MULTIPLE)

1. A-> B -> E

2. A-> C -> E-> F -> H -> I

3. A-> C-> F-> H -> I

4. A->B->G

5.A->B->F->H->I

Part 4. Suppose each activity has a standard deviation of 0.5 days. What is the probability that the project can be completed in 10 days? (If there are multiple critical paths, then use the critical path with the largest standard deviation.)

A. .04 or less

B. More than .04 but less than .15

C. .15 or more

Part 5. What is the least costly way to crash the project in order to complete it one day earlier? (Can select multiple)

		B by 1 day
		D by 2 days
		C by 1 day
		E by 1 day
		F by 1 day
		C by 2 days

Answer 1

Activity	Duration
A	4
B	3
C	3
D	2
E	5
F	2
G	3
H	1
I	2
Path	Length
ABD	9
ABE	12
ABG	10
ABFHI	12
ACFHI	12
Critical paths	expected project completion time (days)
ABFHI,ACFHI, ABE	12

Part1. The total expected project completion time is:

Answer 1---- D. none of the above

Part 2. What is the effect of a delay of 1 day in distributing tickets?

Answer 2
B. the project will delay by one day

Because Activity E lies on Critical Path (ABE), any delay for the activites lying on critical path would cause a equal delay on the project completion

Part 3. What is the critical path for this project (CAN SELECT MULTIPLE)

1. A-> B -> E - YES

3. A-> C-> F-> H -> I - YES

5. A->B->F->H->I - YES

Part 4. Suppose each activity has a standard deviation of 0.5 days. What is the probability that the project can be completed in 10 days? (If there are multiple critical paths, then use the critical path with the largest standard deviation.)

Answer A. .04 or less

Activity	Duration	StDev	Variance (StDev^2)
A	4	0.5	0.25
B	3	0.5	0.25
C	3	0.5	0.25
D	2	0.5	0.25
E	5	0.5	0.25
F	2	0.5	0.25
G	3	0.5	0.25
H	1	0.5	0.25
I	2	0.5	0.25
Path	Length		Variance
ABD	9
ABE	12		0.75
ABG	10
ABFHI	12		1.25
ACFHI	12		1.25

Critical path	expected project completion time	Valiance	Standard Deviation, σ (=sqrt(variance))
ABFHI,ACFHI	12	1.25	1.118
If there are more than 1 critical paths, then the project duration will be calculated using the path with highest Variance

Critical Path	ABFHI,ACFHI
mean project time (u) of critical path is=	12.00
Required completion time	10
standard deviation= sqrt(variance)=	1.118
because Z= (given completion time- u)/standard deviation	-1.79
P(z)= using NORM.S.DIST(z,true)	0.0367
the probability of completing within 10 days=	0.0367

Dear Student,
Please note : Chegg's guidelines mandate to solve one question (or 1st four sub-parts of the very same question) at a time. I would request you to post your question again. At that time, kindly add a comment along with the Question mentioning the specific remaining questions (or sub-parts) to be answered.

Please ask, if you have any doubts through the comment section. Do rate the answer.