Question

In the following table the activities with their precedence sequence and expected time (days) are listed for a project: Activity Immediate Predecessor(s) Time (days) - ITMO OWNono Ana E, F D GH a) The activities on the critical path are b) The project length is days. A-B-E-G-1 A-B-D-H-1 A-C-F-G-

Answer 1

ACTIVITY	DURATION	ES	EF	LS	LF	SLACK
A	7	0	7	0	7	0
B	2	7	9	8	10	1
C	4	7	11	7	11	0
D	5	9	14	10	15	1
E	5	9	14	11	16	2
F	5	11	16	11	16	0
G	2	16	18	16	18	0
H	3	14	17	15	18	1
I	6	18	24	18	24	0

FORWARD PASS

1. Go from left to right in a network.

2. ES = maximum of the EF value from all the direct predecessors.

3. EF = ES + Duration.

BACKWARD PASS

1. Go from right to left in a network.

2. LF = minimum of the LS value from all the direct predecessors.

3. LS = LF - Duration.

CRITICAL PATH

1. Total slack of all activities should be 0.

2. The total duration of all the activities should be the highest.

3. Slack = LF - EF or LS - ES

CRITICAL PATH & DURATION

A + C + F + G + I = 24