hi could you help me find the margin of error , i have no idea what it is.
A 95% confidence level has significance level of 0.05 and critical value is,
The margin of error ( E ) is,
The 95% confidence interval is,
Therefore, the 95% confidence interval for is from -2.6062 to 0.0062 , with the margin of error 1.3062
hi could you help me find the margin of error , i have no idea what...
a) Use the t-distribution to find a confidence interval for a difference in means μ1-μ2 given the relevant sample results. Give the best estimate for μ1-μ2, the margin of error, and the confidence interval. Assume the results come from random samples from populations that are approximately normally distributed. A 90% confidence interval for μ1-μ2 using the sample results x¯1=8.8, s1=2.7, n1=50 and x¯2=13.3, s2=6.0, n2=50 Enter the exact answer for the best estimate and round your answers for the margin...
Independent random samples were selected from two quantitative populations, with sample sizes, means, and standard deviations given below. n1 = n2 = 60 x1 = 125.3 x2 = 123.4 s1 = 5.7 s2 = 6.1 a) Construct a 95% confidence interval for the difference in the population means (μ1 − μ2). (Round your answers to two decimal places.) to b) Find a point estimate for the difference in the population means. c) Calculate the margin of error. (Round your answer...
Use a t-distribution to find a confidence interval for the difference in means μd=μ1-μ2 using the relevant sample results from paired data. Assume the results come from random samples from populations that are approximately normally distributed, and that differences are computed using d=x1-x2 . A 95% confidence interval for μd using the paired difference sample results x¯d=3.1, sd=2.4, nd=30. Give the best estimate for μd, the margin of error, and the confidence interval. Enter the exact answer for the best...
Use the normal distribution to find a confidence interval for a proportion p given the relevant sample results. Give the best point estimate for p , the margin of error, and the confidence interval. Assume the results come from a random sample. A 95% confidence interval for the proportion of the population in Category A given that 18% of a sample of 450 are in Category A. Round your answer for the point estimate to two decimal places, and your...
A market research firm supplies manufacturers with estimates of the retail sales of their products from samples of retail stores. Marketing managers are prone to look at the estimate and ignore sampling error. An SRS of 29 stores this year shows mean sales of 77 units of a small appliance, with a standard deviation of 15 units. During the same point in time last year, an SRS of 18 stores had mean sales of 92.75 units, with standard deviation 12.1...
Having the worst time trying to answer these three questions below. Assume that σ21=σ22=σ2. Calculate the pooled estimator of σ2 when the first sample gives s21=128 and the second independent sample gives s22= 128, and n1=n2=36. Give your answer to two decimal places , do not round up or down. And .. Two independent random samples have been slected ; 111 observations from population one and 143 observations from population two. From previous experience it is known that the standard...
Consider the following competing hypotheses and accompanying sample data drawn independently from normally distributed populations. (Note: the automated question following this one will ask you confidence interval questions for this same data, so jot down your work.) H0: μ1 − μ2 = 0 HA: μ1 − μ2 ≠ 0 x−1x−1 = 60 x−2x−2 = 56 σ1 = 1.62 σ2 = 10.20 n1 = 25 n2 = 25 Calculate the value of the test statistic. (Negative values should be indicated by...
You may need to use the appropriate appendix table or technology to answer this question. The following results come from two independent random samples taken of two populations. Sample 1 Sample 2 n1 = 50 n2 = 25 x1 = 13.6 x2 = 11.6 σ1 = 2.3 σ2 = 3 (a) What is the point estimate of the difference between the two population means? (Use x1 − x2.) (b) Provide a 90% confidence interval for the difference between the two...
Use the t-distribution to find a confidence interval for a difference in means μ 1 - μ 2 given the relevant sample results. Give the best estimate for μ 1 - μ 2, the margin of error, and the confidence interval. Assume the results come from random samples from populations that are approximately normally distributed. A 95% confidence interval for μ 1 - μ 2 using the sample results x ¯ 1 = 533 , s 1 = 137 ,...
If you wish to estimate a population mean with a margin of error MEequals=0.33 using a 95% confidence interval and you know from prior sampling that σ2 is approximately equal to 4.6 how many observations would have to be included in your sample? The number of observations that would have to be included in your sample is (______) (Round up to the nearest observation.)