first convert all the slab load to live load acting on joint
6" spaced = 6X ( 500 + 200) = 4200 lb/ ft
5' spaced = 5 X 700 = 3500 lb/ft
load on beam AF and BE = 3 X 700 = 2100 lb/ft
load on beam FG and DH = 2.5 X 700 = 1750 lb/ft
6' joint = ( 20 X 4200) / 2 = 42000 lb / ft
5' joint = (15 X 3500) / 2 = 26250 lb each side
load on column A and F due to beam
(20 X 2100)/2 = 21000 lb on B and E
load on column F, D, G and H due to beam FD and GH = (15 X 1750) /2
A = 105000 lb
B = 105000 lb
C = 0 lb
D = 39375 lb
2. A roof plan for a small building is shown below. The roof is composed of...
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I don’t want the answers just a plan on how to solve the
problem
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show work please!!
1. For the given framing plan, first identify all unique beams and columns. After that, find out the final load transferred on each beam and girder. Finally draw load diagrams for all beams and girders, and determine the support reactions (70 Points) 50 ft 50 ft 50 ft 25 ft 25 ft 0 25 ft 25 ft Use Live load 110 PSF . Dead load excluding weight of the slab 15 PSF .Thickness of concrete slab 6...
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