a)
from above line equation : y^ =-3.3667+2.4931x
b)
correlation coefficient r= | Sxy/(√Sxx*Syy) = | 0.801 |
null hypothesis: Ho: ρ | = | 0 | |
Alternate Hypothesis: Ha: ρ | ≠ | 0 | |
0.05 level,two tail test and n-2= 21 df, critical t= | 2.080 | ||
Decision rule: reject Ho if absolute value of test statistic |t|>2.08 | |||
correlation coefficient r= | Sxy/(√Sxx*Syy) = | 0.801 | |
test stat t= | r*(√(n-2)/(1-r2))= | 6.123 |
P value = | 0.000 |
since p value <0.05 , we reject the null and conclude there is a significant correlation between two variables
c)
predicted val=-3.3667+5*2.4931= | 9.10 |
X is the amount of chocolate consumption y is the Nobel Laureate rate Chocolate 4.5 10.2...
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