The results of a test cross reveal that the offspring resemble the parent being tested. This...
The results of a test cross reveal that the offspring resemble the parent being tested. This parent must be a) Heterozygous b) Recessive c) Self-pollinated d) Homozygous e) haploid
Homework Answers
d) Homozygous
Test cross is a cross performed between F1 offspring and homozygous recessive parent, to check whether an F1 offspring is homozygous or hetrozygous.
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The results of a test cross reveal that the offspring resemble
the parent being tested. This...
When considering a single character, the progeny of a test cross have a 1:1 ratio of...
When considering a single character, the progeny of a test cross have a 1:1 ratio of dominant to recessive phenotypes. 1) the phenotype of the non-tester parent is a) recessive b) dominant c) homozygous d) heterozygous e) not enough information to solve this problem 2) The genotype of the non-tester parent is a) homozygous dominant b) heterozygous c) homozygous recessive d) hemizygous e) not enough information to solve this problem
1. In a monohybrid cross, (a) only one trait is being considered. ib) the parents are...
1. In a monohybrid cross, (a) only one trait is being considered. ib) the parents are always dominant. is the parents are always heterozygous. (d) no hybrid is produced. 7. The gametophyte of a fomu (a) haploid. (b) photoautotrophic. (c) a structure that produces eggs and/or sperm (d) all of the above 8. A chi-square test is used to (a) determine if experimental data adequately matches what was expected. (b) analyze a Punnett square. (c) determine parental genotypes producing a...
In a test cross to determine gene linkage, at least 50% of the offspring should have...
In a test cross to determine gene linkage, at least 50% of the offspring should have the same allele arrangement as the heterozygous parent. The best explanation is that recombinant chromosomes are balanced during fertilization. two of the chromosomes in a homologous pair do not participate in synapsis. at least 50% of the recombination events result in the same combination of alleles. double cross-overs resemble the parent allele arrangement and occur in the greatest frequency
Would a dihybrid cross between a heterozygous parent (BbSs) and a homozygous dominant parent (BBSS) end...
Would a dihybrid cross between a heterozygous parent (BbSs) and a homozygous dominant parent (BBSS) end up as independently assorted genes? The results of offspring would be 100% dominant.
12. What is a suspected heterozygous individual crossed with in a test cross? A. Homozygous dominant...
12. What is a suspected heterozygous individual crossed with in
a test cross?
A. Homozygous dominant
B. Homozygous recessive
C. Heterozygous dominant
D. Heterozygous recessive
13. Which of the following genotypes is possible in the
offspring of a homozygous male with blood group A and a female with
blood group B?
The answers are 12B, 13B, 14C can you explain how?
Α. ΙΑΙΑ 14. What type of inheritance is shown in this pedigree chart? Key: Affected O Carrier A. X-linked...
A heterozygous parent self fertilizes and the progeny are collected. Eight of these offspring form wild-type...
A heterozygous parent self fertilizes and the progeny are collected. Eight of these offspring form wild-type plants and six become homozygous recessive mutants? Calculate the probabilities using the A) binomial theorem and B) chi-square analyses (estimate this to the nearest hundredth by assuming there is a linear relationship between the nearest two data points in the chi-square chart). C) Explain why these two probabilities differ.
Which of the following is true regarding dihybrid crosses? A. Each parent involved in the cross...
Which of the following is true regarding dihybrid crosses? A. Each parent involved in the cross is heterozygous for at least one of the two genes being assessed. B. Two gene loci are assessed and the parents can be any genotype at these two loci. C. There are 9 different fertilization possibilities. D. The ratio 9:3:3:1 means that of the possible outcomes in offspring; 9/16 will express the dominant phenotype for both loci, 3/16 will express the dominant phenotype for...
17. In a simple monohybrid cross the individuals of 100% known genotype in the F2 offspring,...
17. In a simple monohybrid cross the individuals of 100% known genotype in the F2 offspring, are which of these? a) the heterozygous individuals b) the homozygous dominant individuals c) the homozygous recessive individuals d) you could not determine the geneotype of any offspring without performing additional tests. 18. If an individual contains two alleles for a particular gene and the two alleles are different from each other, the individual is said to be: a) homozygous dominant b) homozygous recessive...
Please answer these questions Dihybrid Test Cross PpTt x pptt Heterozygous for both genes makes 4...
Please answer these questions
Dihybrid Test Cross PpTt x pptt Heterozygous for both genes makes 4 types of gametes: PPTT x pptt Homozygous dominant for both genes makes 1 type of gamete: Homozygous recessive for Homozygous recessive for both genes makes 1 type of gamete: both genes makes 1 type of gamete: All of the offspring will have What type of offspring will the genotype the phenotype result?
Please show your work. 9. Maize carries two genes for disease resistance, msvi, msv2, on the...
Please show your work.
9. Maize carries two genes for disease resistance, msvi, msv2, on the same chromosome. They are 20 map units apart as shown: A plant is heterozygous for the two genes, in the following configuration: msvl msv1 / Msv1 Msv2 (i.e. the two recessive alleles are on the same chromosome). It is self pollinated. What proportion of the offspring will be homozygous recessive for both genes? Choose best answer: A) 0.01 B) 0.16 C) 0.25 D) 0.40...
1. In a monohybrid cross, (a) only one trait is being considered. ib) the parents are always dominant. is the parents are always heterozygous. (d) no hybrid is produced. 7. The gametophyte of a fomu (a) haploid. (b) photoautotrophic. (c) a structure that produces eggs and/or sperm (d) all of the above 8. A chi-square test is used to (a) determine if experimental data adequately matches what was expected. (b) analyze a Punnett square. (c) determine parental genotypes producing a...
In a test cross to determine gene linkage, at least 50% of the offspring should have the same allele arrangement as the heterozygous parent. The best explanation is that recombinant chromosomes are balanced during fertilization. two of the chromosomes in a homologous pair do not participate in synapsis. at least 50% of the recombination events result in the same combination of alleles. double cross-overs resemble the parent allele arrangement and occur in the greatest frequency
12. What is a suspected heterozygous individual crossed with in
a test cross?
A. Homozygous dominant
B. Homozygous recessive
C. Heterozygous dominant
D. Heterozygous recessive
13. Which of the following genotypes is possible in the
offspring of a homozygous male with blood group A and a female with
blood group B?
The answers are 12B, 13B, 14C can you explain how?
Α. ΙΑΙΑ 14. What type of inheritance is shown in this pedigree chart? Key: Affected O Carrier A. X-linked...
A heterozygous parent self fertilizes and the progeny are collected. Eight of these offspring form wild-type plants and six become homozygous recessive mutants? Calculate the probabilities using the A) binomial theorem and B) chi-square analyses (estimate this to the nearest hundredth by assuming there is a linear relationship between the nearest two data points in the chi-square chart). C) Explain why these two probabilities differ.
Please answer these questions
Dihybrid Test Cross PpTt x pptt Heterozygous for both genes makes 4 types of gametes: PPTT x pptt Homozygous dominant for both genes makes 1 type of gamete: Homozygous recessive for Homozygous recessive for both genes makes 1 type of gamete: both genes makes 1 type of gamete: All of the offspring will have What type of offspring will the genotype the phenotype result?
Please show your work.
9. Maize carries two genes for disease resistance, msvi, msv2, on the same chromosome. They are 20 map units apart as shown: A plant is heterozygous for the two genes, in the following configuration: msvl msv1 / Msv1 Msv2 (i.e. the two recessive alleles are on the same chromosome). It is self pollinated. What proportion of the offspring will be homozygous recessive for both genes? Choose best answer: A) 0.01 B) 0.16 C) 0.25 D) 0.40...
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