It is given that the genotype of parent 1 is a+/a- b+/b
a) Four types of gametes will be produced. These are: a+b+, a-b, a+b, a-b+
Parent 2 has genotype a/a- b/b
Two types of gametes will be produced by this parent. These will be ab and a-b
The results will be 8 types of genotypes: a+/a b+/b, a-/a b/b, a+/a b/b, a-/a b+/b
a+/a- b+/b, a-/a- b/b, a+/a- b/b, a-/a-b+/b
b)
The results are not showing independent assortment. Had it been independent assortment, then all the above 8 genotypes would have been there, and in equal proportion.
c)
Total genotypes = 38+37+12+13=100
Parental types = 38+37 = 75
Recombinants = 12+13= 25
Since parental types >>>recombinants it indicates that genes are linked. The linked genes are a+/b+ and a-/b
d)
fruit fly of genotype a a b h (parent I)is crossed to another fruit lty of...
6. In Cross 1, a yellow eyed, long wing fruit fly from a pure breeding strain is mated to a red eye, short wing fruit fly from a pure breeding strain. All of their offspring (F1) had red eyes and long wings. In Cross 2, one of the F1 offspring is mated to a fly with yellow eyes and short wings, and this cross gave the following F2 population: 194 flies with long wings and red eyes, 796 flies with...
2. Three genes and their mutations are found on the third chromosome in fruit fly Drosophila melanogaster. Of these three genes, scarlet eyes (st) are recessive to red eyes (st"), cbony body color (eb) is recessive to gray body color (eb"), and spineless (ss), the st presence of small bristles, is recessive to normal bristles (ss). You eb SS were given a heterozygous fly (st'st eb'eb ss'ss) and were asked to eb ss design an experiment to map the distance...
Mendel crossed green and yellow peas and all of the hybrids were yellow. When the hybrids self-fertilized to get another generation about what proportion of their progeny were yellow? a. 1/4 of them b. about half of them c. all of them d. none of them 6. 3/4 of them QUESTION 2 You find a patch of peas in which 3/4 of the peas are yellow and 1/4 of the peas were green. Assuming that all of the peas were...
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5. In an organism where 2N = 20, how many unique gametes could be produced due to independent assortment alone (not considering crossing over)? Briefly explain. 6. One of the autosomal loci controlling eye color in fruit flies has two alleles, one for brown eyes and the other for red eyes. Fruit flies from a true-breeding line with brown eyes were crossed with flies form a true-breeding line with red eyes. The Fı...
Question 12 only.
Punnett's square analysis for the parental cross r Rr Rr 9) If we used the above offspring (F1) in a new cross, what would be the genotypes and phenotypes of the offspring of the Fz generation? 10) What is the genotypic ratio of the F2 generation? 11) What is the phenotypic ratio of the F2 generation? 12) What would be the genotypic and phenotypic ratios of offspring from a cross between a homozygous recessive parent (r r)...
Nameindulia Los Drosophila Genetics Predictions-L113 (20 pts.) Part I. Meiosis and Punnett Squares Remember, whenever you use Punnett Squares to solve genetics problems, be sure you are completing each of the following steps: 1) Identify the genotypes of the parents. 2) For the specific traits of interest, figure out what kinds of haploid gametes each parent can make. In each gamete, there should be one allele for each trait of interest. If there is more than one trait, make sure...
2. In a testcross of a female Drosophila heterozygous for three linked recessive genes, the following phenotypes of progeny were obtained: 442 435 at bt d a bd at bd a bt d at bd a bt di at bt dt a bd Total ONEN 1000 A) Write out the parental genotype of the heterozygous parent indicating the correct allele configuration and gene order B) Construct a map of the genes and indicate the map-distances based on the data shown...
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1) Consider a single germ cell with the genotype A/a;B/b undergoing meiosis. Which of the following are possible genotypes for the set of four gametes resulting from meiosis of this single germ cell? (assume that there is NOT any nondisjunction) A, a, B, b Aa, Aa, Bb, Bb AB, Ab, aB, ab Ab, Ab, aB, aB aa, AA, BB, bb 2) From true-breeding stocks, a female fly with no eyes (mutation in eyeless (ey) gene) and no wings (mutation in...