Question

Hello! Can someone solve this question? Thank you!

5. The value of Ke for the following reaction is 10.5 at 227 °C. CO(g) + 2Hz(8) + CH,OH(g) (a) What is the value of Kc for the following reaction? CH3OH(g) + CO(g) + 2H2(g) (b) What is the value of Kc for the following reaction? 3CO(g) + 6H2(g) 6H.(g) + 3CH2OH(g) (c) What is the value for Kp for the following reaction? CO(g) + 2H2(g) CH3OH(g)

Answer 1

From the given reaction,
Kc = [CH3OH]/[CO][H2]^2
= 10.5

a)
For this reaction,
Kc’ = [CO][H2]^2/[CH3OH]
= 1/Kc
= 1/10.5
= 0.0952
Answer: 0.0952

B)
For this reaction,
Kc’ = [CH3OH]^3/[CO]^3[H2]^6
= ([CH3OH]/[CO][H2]^2)^3
= (Kc)^3
= (10.5)^3
= 1.16*10^3
Answer: 1.16*10^3

C)
T= 227.0 oC
= (227.0+273) K
= 500 K
Δ n = number of gaseous molecule in product - number of gaseous molecule in reactant
Δ n = -2

use:
Kp= Kc (RT)^Δ n
Kp = 10.5*(0.08206*500.0)^(-2)
Kp = 6.237*10^-3
Answer: 6.24*10^-3