Question

A homozygous variety of opium poppy (Papaver somniferum Laciniatum) with lacerate leaves was crossed with another homozygous variety with normal leaves. All the Fj had lacerate leaves (jagged-edged leaves). Two F1 plants were crossed to produce the F2. Of the F2, 249 had lacerate leaves and 16 had normal leaves. How are lacerate leaves determined in the opium poppy? two genes, with a dominant allele at either or both loci one gene, with codominant alleles at a single locus two genes, with a dominant allele at both loci two genes, where one allele at a single locus is recessive lethal Give genotypes for all the plants in the P, F1, and F2 generations. Some generations will have more than one genotype. P Answer Bank AABB aabb F2 (lacerate) A_B_ аав F2 (normal) 4_bb | Аавь

Answer 1

The lacerate leaves are best described as ;

Option A two genes with dominant allele at either or both loci as the trait is visible if genotype is Aa or AA.

Option b - incorrect- as it states about codominant which is not present in this case after crossing only dominant and recessive traits are visible nothing intermittent is seen.

Option c- incorrect as it is a type of outcross of homologous organism for alternate alleles at one locus.

Option d - incorrect as the trait visible is in majority ratio which is possible only when the gene is a dominant one and it cant be a recessive one.

The answer for the genotypes of the various generations is mentioned in the picture attached.

00000000000 o F P= AA Claminaht.., lacerate Leaves). paaa (Recessine normal leancs). A4..... aa . Cross = Aa Aa ooo ........ . .. .... AA Aa aa n AA AAAA AAAaaaaa - For - e Aa AAA aAAaaAaaa ooo aa Akaa Aaaa faaaa only this.gendlūpe will have mdrmal Cleanes fest. all the genotypes will have lacezale- leanes F9 lacrati = AAAA, AAAA, AAaa..,AAAQ.. Aaaa to normal = aaaa o o o _