Question

Gene X is 3000 base pairs in length. How many CODONS make up this GeneX? (1 pt) How many amino acids would be in the protein
0 0
Add a comment Improve this question Transcribed image text
Answer #1

First Question:

The answer will be 1000.

Explanation: Each codon is consisting of 3 base pairs. Thus, in 3000 base pairs gene X will have 3000/3 or 1000 codons.

Second Question:

The answer will be 999.

Explanation: Gene X contains 1000 codons (Determined in previous question). Of these codons one will be stop codon which will not translate into an amino acid. Thus, gene X will have 999 amino acids.

Third Question:

The answer will be 303.

Explanation: Each amino acid will be coded by one codon & each codon consists of 3 base pairs. Thus, 100 amino acids will have (100 x 3) or 300 base pairs. Further, there will be one stop codon which have 3 base pairs. Thus, gene Y will have (300+3) or 303 base pairs.

Fourth Question:

The answer will be 101.

Explanation: Gene Y contains 303 base pairs (Determined in previous question). Each codon is consisting of 3 base pairs. Thus, in 303 base pairs gene Y will have 303/3 or 101 codons.

Fifth Question:

The answer will be 119.

Explanation: Gene Z will have 360/3 or 120 codons. Of these codons, one will be stop codon. Thus, there will be 119 codons that will code for an amino acid. Thus, there will be 119 amino acids.

Sixth Question:

The answer will be 120.

Explanation: Already explained in previous question that gene Z will have 120 codons.

Add a comment
Know the answer?
Add Answer to:
Gene X is 3000 base pairs in length. How many CODONS make up this GeneX? (1...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • The sequence of the gene for alcohol dehydrogenase is shown below. AATGCGTTTACCAAGCGTACAGTGTGCAAA Write the complementary strand...

    The sequence of the gene for alcohol dehydrogenase is shown below. AATGCGTTTACCAAGCGTACAGTGTGCAAA Write the complementary strand of nucleic acid that would be synthesized during transcription below the original strand. 2 pts) How many codons are in the alcohol dehydrogenase Rene? (1 pt) How many amino acids would be in the alcohol dehydrogenase enzyme? (1 pt) TRANSLATION 1 codon base pairs (1 pt) 1 codon amino acids (1 pt) 3 base pairs = amino acids (1 pt) A molecule of tRNA...

  • A gene contains 141 codons. How many nucleotides are present in thegene's coding sequence? How many...

    A gene contains 141 codons. How many nucleotides are present in thegene's coding sequence? How many amino acids are expected to bepresent in the polypeptide encoded by this gene?

  • aus: 99 Consider the following DNA sequence: TTAGATCGTAAAGTGCAATGGGATCATATG What would be the mRNA transcribed from this...

    aus: 99 Consider the following DNA sequence: TTAGATCGTAAAGTGCAATGGGATCATATG What would be the mRNA transcribed from this DNA sequence? ots)? 10 AAU CUA G CA unU CAC Gui ACC CUA GUAU- How many codons does the sequence contain 21 th A How many amino acids make up this protein? (1 pt) List the amino acids, in order, that make up this protein using the chart provided. (5 pts) Referring to the mRNA strand constructed in Question #3, list the tRNA anti-codons...

  • Below is the genomic DNA of gene X, a 3 exon gene that encodes a 131 amino acid single pass trans...

    why is E the answer Below is the genomic DNA of gene X, a 3 exon gene that encodes a 131 amino acid single pass transmembrane protein. Shown are the transcriptional start site, splice donor, acceptor and branch sites and translational start and stop codons. Transcriptional start EXON 1 INTRON 1 EXON 2 INTRON 2 EXON 3 Spfice Donor Splice Acceptor Polyadenylation signal Branch point 17. Treatment with ethidium bromide, an intercalating agent, caused DNA polymerase to add an extra...

  • Find the forward and reverse primer at 68 degrees C. How many base pairs will the...

    Find the forward and reverse primer at 68 degrees C. How many base pairs will the PCR product be that is generated by using these primers? How many amino acids is the predicted protein encoded by this open reading frame? Here's the complete genome of SARS coronavirus >Genome ATGTTTATTTTCTTATTATTTCTTACTCTCACTAGTGGTAGTGACCTTGACCGGTGCACCACTTTTGATGATGTTCAAGCTCCTAATTACACTCAACATACTTCATCTATGAGGGGGGTTTACTATCCTGATGAAATTTTTAGATCAGACACTCTTTATTTAACTCAGGATTTATTTCTTCCATTTTATTCTAATGTTACAGGGTTTCATACTATTAATCATACGTTTGGCAACCCTGTCATACCTTTTAAGGATGGTATTTATTTTGCTGCCACAGAGAAATCAAATGTTGTCCGTGGTTGGGTTTTTGGTTCTACCATGAACAACAAGTCACAGTCGGTGATTATTATTAACAATTCTACTAATGTTGTTATACGAGCATGTAACTTTGAATTGTGTGACAACCCTTTCTTTGCTGTTTCTAAACCCATGGGTACACAGACACATACTATGATATTCGATAATGCATTTAATTGCACTTTCGAGTACATATCTGATGCCTTTTCGCTTGATGTTTCAGAAAAGTCAGGTAATTTTAAACACTTACGAGAGTTTGTGTTTAAAAATAAAGATGGGTTTCTCTATGTTTATAAGGGCTATCAACCTATAGATGTAGTTCGTGATCTACCTTCTGGTTTTAACACTTTGAAACCTATTTTTAAGTTGCCTCTTGGTATTAACATTACAAATTTTAGAGCCATTCTTACAGCCTTTTCACCTGCTCAAGACATTTGGGGCACGTCAGCTGCAGCCTATTTTGTTGGCTATTTAAAGCCAACTACATTTATGCTCAAGTATGATGAAAATGGTACAATCACAGATGCTGTTGATTGTTCTCAAAATCCACTTGCTGAACTCAAATGCTCTGTTAAGAGCTTTGAGATTGACAAAGGAATTTACCAGACCTCTAATTTCAGGGTTGTTCCCTCAGGAGATGTTGTGAGATTCCCTAATATTACAAACTTGTGTCCTTTTGGAGAGGTTTTTAATGCTACTAAATTCCCTTCTGTCTATGCATGGGAGAGAAAAAAAATTTCTAATTGTGTTGCTGATTACTCTGTGCTCTACAACTCAACATTTTTTTCAACCTTTAAGTGCTATGGCGTTTCTGCCACTAAGTTGAATGATCTTTGCTTCTCCAATGTCTATGCAGATTCTTTTGTAGTCAAGGGAGATGATGTAAGACAAATAGCGCCAGGACAAACTGGTGTTATTGCTGATTATAATTATAAATTGCCAGATGATTTCATGGGTTGTGTCCTTGCTTGGAATACTAGGAACATTGATGCTACTTCAACTGGTAATTATAATTATAAATATAGGTATCTTAGACATGGCAAGCTTAGGCCCTTTGAGAGAGACATATCTAATGTGCCTTTCTCCCCTGATGGCAAACCTTGCACCCCACCTGCTCTTAATTGTTATTGGCCATTAAATGATTATGGTTTTTACACCACTACTGGCATTGGCTACCAACCTTACAGAGTTGTAGTACTTTCTTTTGAACTTTTAAATGCACCGGCCACGGTTTGTGGACCAAAATTATCCACTGACCTTATTAAGAACCAGTGTGTCAATTTTAATTTTAATGGACTCACTGGTACTGGTGTGTTAACTCCTTCTTCAAAGAGATTTCAACCATTTCAACAATTTGGCCGTGATGTTTCTGATTTCACTGATTCCGTTCGAGATCCTAAAACATCTGAAATATTAGACATTTCACCTTGCGCTTTTGGGGGTGTAAGTGTAATTACACCTGGAACAAATGCTTCATCTGAAGTTGCTGTTCTATATCAAGATGTTAACTGCACTGATGTTTCTACAGCAATTCATGCAGATCAACTCACACCAGCTTGGCGCATATATTCTACTGGAAACAATGTATTCCAGACTCAAGCAGGCTGTCTTATAGGAGCTGAGCATGTCGACACTTCTTATGAGTGCGACATTCCTATTGGAGCTGGCATTTGTGCTAGTTACCATACAGTTTCTTTATTACGTAGTACTAGCCAAAAATCTATTGTGGCTTATACTATGTCTTTAGGTGCTGATAGTTCAATTGCTTACTCTAATAACACCATTGCTATACCTACTAACTTTTCAATTAGCATTACTACAGAAGTAATGCCTGTTTCTATGGCTAAAACCTCCGTAGATTGTAATATGTACATCTGCGGAGATTCTACTGAATGTGCTAATTTGCTTCTCCAATATGGTAGCTTTTGCACACAACTAAATCGTGCACTCTCAGGTATTGCTGCTGAACAGGATCGCAACACACGTGAAGTGTTCGCTCAAGTCAAACAAATGTACAAAACCCCAACTTTGAAATATTTTGGTGGTTTTAATTTTTCACAAATATTACCTGACCCTCTAAAGCCAACTAAGAGGTCTTTTATTGAGGACTTGCTCTTTAATAAGGTGACACTCGCTGATGCTGGCTTCATGAAGCAATATGGCGAATGCCTAGGTGATATTAATGCTAGAGATCTCATTTGTGCGCAGAAGTTCAATGGACTTACAGTGTTGCCACCTCTGCTCACTGATGATATGATTGCTGCCTACACTGCTGCTCTAGTTAGTGGTACTGCCACTGCTGGATGGACATTTGGTGCTGGCGCTGCTCTTCAAATACCTTTTGCTATGCAAATGGCATATAGGTTCAATGGCATTGGAGTTACCCAAAATGTTCTCTATGAGAACCAAAAACAAATCGCCAACCAATTTAACAAGGCGATTAGTCAAATTCAAGAATCACTTACAACAACATCAACTGCATTGGGCAAGCTGCAAGACGTTGTTAACCAGAATGCTCAAGCATTAAACACACTTGTTAAACAACTTAGCTCTAATTTTGGTGCAATTTCAAGTGTGCTAAATGATATCCTTTCGCGACTTGATAAAGTCGAGGCGGAGGTACAAATTGACAGGTTAATTACAGGCAGACTTCAAAGCCTTCAAACCTATGTAACACAACAACTAATCAGGGCTGCTGAAATCAGGGCTTCTGCTAATCTTGCTGCTACTAAAATGTCTGAGTGTGTTCTTGGACAATCAAAAAGAGTTGACTTTTGTGGAAAGGGCTACCACCTTATGTCCTTCCCACAAGCAGCCCCGCATGGTGTTGTCTTCCTACATGTCACGTATGTGCCATCCCAGGAGAGGAACTTCACCACAGCGCCAGCAATTTGTCATGAAGGCAAAGCATACTTCCCTCGTGAAGGTGTTTTTGTGTTTAATGGCACTTCTTGGTTTATTACACAGAGGAACTTCTTTTCTCCACAAATAATTACTACAGACAATACATTTGTCTCAGGAAATTGTGATGTCGTTATTGGCATCATTAACAACACAGTTTATGATCCTCTGCAACCTGAGCTTGACTCATTCAAAGAAGAGCTGGACAAGTACTTCAAAAATCATACATCACCAGATGTTGATCTTGGCGACATTTCAGGCATTAACGCTTCTGTCGTCAACATTCAAAAAGAAATTGACCGCCTCAATGAGGTCGCTAAAAATTTAAATGAATCACTCATTGACCTTCAAGAATTGGGAAAATATGAGCAATATATTAAATGGCCTTGGTATGTTTGGCTCGGCTTCATTGCTGGACTAATTGCCATCGTCATGGTTACAATCTTGCTTTGTTGCATGACTAGTTGTTGCAGTTGCCTCAAGGGTGCATGCTCTTGTGGTTCTTGCTGCAAGTTTGATGAGGATGACTCTGAGCCAGTTCTCAAGGGTGTCAAATTACATTACACATAA

  • How many nucleotides would be expected in the exons for a gene coding for a protein...

    How many nucleotides would be expected in the exons for a gene coding for a protein with 406 amino acids? 135 1221 134 1218 1225

  • How many nucleotides would be expected in the exons for a gene coding for a protein...

    How many nucleotides would be expected in the exons for a gene coding for a protein with 406 amino acids? Group of answer choices 135 1221 134 1218 1225

  • Chapter 15: 1. What is the significance of the fact that many synonymous codons differ in...

    Chapter 15: 1. What is the significance of the fact that many synonymous codons differ in the third nucleotide position? 2. Define the following terms as they apply to the genetic code: a. Reading frame b. Overlapping code C. Nonoverlapping code d. Initiation codon e. Termination codon f. Sense codon 8. Nonsense codon h. Universal code i. Nonuniversal code 3. What role do the initiation factors play in protein synthesis? 4. Compare and contrast the process of protein synthesis in...

  • want to double check! 25. Th e DNA sequences encoding the initiation whese parated bcoding the...

    want to double check! 25. Th e DNA sequences encoding the initiation whese parated bcoding the initiation and termination codons of a certain protein amino acids in length. there of the protei nucleotides on a certain organism's chromosome; however ssuming that there has been no post-translational processing elined from this gene is translated, the protein product is only 250 A. The RNA was synthesized in a bacterial cell n, what can you conclude from these observations? The RNA was synthesized...

  • Below is a schematic of gene Hemoglobin beta subunit (HBS), which encodes protein HBS. The promoter...

    Below is a schematic of gene Hemoglobin beta subunit (HBS), which encodes protein HBS. The promoter region is indicated by the dotted box. Transcriptions begins immediately following the promoter. The mature mRNA produced by this gene would be approximately how many nucleotides long? A) 100 B) 200 C) 3000 D) 5000 E) 7000 1. Below is a schematic of gene Hemoglobin beta subunit (HBS), which encodes protein HBS. The promoter region is indicated by the dotted box. Transcription begins immediately...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT