Homework Answers
equilibrium potential=RT/ZF ln ([K+]out/[K+]in)
R=8.314 J/mol
T= temperture in K
37 degree celcius=37+273=310 K
Z= charge of K+=+1
Z=Faradays constant=96485C/mol
[K+]out= 4.5 mM
[K+]in=120 mM
equilibrium potential= (8.314
310/96465)
ln(4.5/120)
=-0.0877V
1 V= 1000 mV
so -0.0877V = -87.7 mV
so the answer is b) -87.7 mV
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