1. (S) << Km - At low concentration fo substrate , velocity is proportional to substrate concentration , the enzyme catalyzed reaction is a first order reaction.
So , the rate is directly proportional to (S).
2. (S) = km , (Efree) = (ES) .
3. (S) >> Km - At high (S) , the velocity become virtually independent of (S) and approaches a maximal limit. Since rate is no longer dependent on (S) at high concentration the enzyme catalyzed reaction obeys zero order kinetics.
So ,Reaction is independent of (S) , (ES) is much higher than (Efree) .
4. Not true for any of these conditions - increasing Etotal will lose km beacuse Km shows the affinity of the enzes towards a particular substrate , it is the intrinsic property if an enzyme that do not depend on the concentration of enzyme instead depends on the binding of enzyme to the substrate .
The Michaelis-Menten equation models the hyperbolic relationship between [S] and the initial reaction rate V for...
The Michaelis-Menten equation models the hyperbolic relationship between (S) and the initial reaction rate V, for an enzyme-catalyzed, single-substrate reaction E+ S E S E+P. The model can be more readily understood when comparing three conditions: [S] << Km, [S] = Km, and [S] >> K. Match each statement with the condition that it describes. Note that "rate" refers to initial velocity Vwhere steady state conditions are assumed. [Exotal) refers to the total enzyme concentration and [Etre) refers to the...
The Michaelis-Menten equation models the hyperbolic relationship between [S) and the initial reaction rate V, for an enzyme-catalyzed, single-substrate reaction E+S ES E + P. The model can be more readily understood when comparing three conditions: [S] << Km, [S] = Km, and [S] >> K. Match each statement with the condition that it describes. Note that "rate" refers to initial velocity V where steady state conditions are assumed. (E l refers to the total enzyme concentration and [Erre refers...
The Michaelis-Menten equation models the hyperbolic relationship between [S] and the initial reaction rate (V0) for an enzyme catalyzed, single substrate reaction: E S ES E P. The model can be more readily understood when comparing three conditions: [S]Km. Match each statement with the condition that it describes. Note: \"Rate\" refers to initial velocity (V0) where steady state conditions are assumed; [Etotal] refers to the total enzyme concentration, and [Efree] refers to the concentration of free enzyme. categories: [S]<<Km, [S]=Km,...
Match each statement with the condition that it describes. Note that "rate" refers to initial velocity V0 where steady state conditions are assumed. [Etotal] refers to the total enzyme concentration and [Efree] refers to the concentration of free enzyme The Michaelis-Menten equation models the hyperbolic relationship between [S] and the initial reaction rate V for an enzyme-catalyzed, single-substrate reaction ES ES EP. The model can be more readily understood when comparing three conditions: [S] << Km, [S] = Km, and...
4. Basic concepts of Michaelis-Menten kinetics. The Michaelis-Menten equation is expression of the relationship between the initial velocity, Vo, of an enzymatic reaction and substrate concentration, [S]. There are three conditions that are useful for simplifying the Michaelis-Menten equation: [S] <<Km; [S] = Km; [S] >> Km. Match each condition with the statement(s) that describe it. TV, Vmox[S] Vo =Vmax m . V Vo - Vmax [S] Km +[S] V. (um/min) max [S] (mm) (a) Doubling [S] will almost double...
3. The Michaelis-Menten Graph also shows the theoretical maximum rate of the enzyme (Vmax), the point where the enzyme is working at its maximum rate (Vmax/2), and amount of substrate needed to bind half of the active sites (Km). Label these points on the graph. Vmax represents: Vm Vmax/2 represents: Reaction velocity v Vmax 2 Km represents: Kim Substrate concentration (5)
The relation between Reaction Velocity and Substrate Concentration: Michaelis-Menten Equation a) At what substrate concentration would an enzyme with a kcat of 30.0 s-1 and a Km of 0.0050 M operate at one-quarter of its maximum rate? b) Determine the fraction of Vmax that would be obtained at the following substrate concentrations: [S]=Km/2, [S]=2Km, [S]=10Km
The Michaelis-Menten equation is often used to describe the kinetic characteristics of an enzyme-catalyzed reaction. S Where v is the velocity or rate, Vmax is the maximum velocity, Km is the +IST Michaelis- Menten constant, and I5 s the substrate concentration. K + S v (uM/min) a) A graph of the Michaelis-Menten equation is a plot of a reaction's initial velocity (Vo) at different substrate concentrations ([S]) 300 Vmax 250 1/2 Vmax First, move the line labeled "Vmax to a...
112 marks] 3. The relationship between initial velocity (V.) and substrate concentration of most of the enzyme- catalized reactions are explained by Michaelis-Menten equation. IMPORTANT: Show the calculations and indicate the units for all your answers. a. For an enzyme which follows the Michaelis-Menten enzyme kinetics, Km is 50 mmol L. Calculate the substrate concentration required to obtain the initial velocity (V.) equivalent to 90% of the maximum velocity (Vmax). b. The Vmax of the above reaction is 250 mmol...
5. The rate of a simple enzyme reaction is given by the standard Michaelis-Menten equation. a. If the Vmax = 354 umol/sec and the KM = 1.5 mm, at what substrate concentration is the rate is 177 umol/sec? b. Using MATLAB, plot a graph of rate versus substrate concentration using the enzyme parameters in part (a) for (S] = 0.5 to 30.0 mM in increments of 0.5 mM). Don't forget to include units on your axes. Include a copy of...