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Suppose that a geneticist discovers a new mutation in Drosophila melanogaster that causes the flies to shake and quiver. She

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Answer #1

When there is found independent assortment, then the each progeny are found in 1/4 proportions of total. 1/4×(650)=162.5

Chi square table:

Phenotype observed flies (O) Expected flies (E) (O-E)^2/E
vg+ qu+ 230 162.5 28.03846
vg qu 224 162.5 23.2753846
vg qu+ 97 162.5 26.4015385
vg+ qu 99 162.5 24.8138462
Total 650 650 102.5292

The answer upto one decimal place is 102.5

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The chi square vakue from chi square table at degree of freedom n-1=4-1=3 and at p =0.05 is 7.815

As our chi square experimental value is more tham chi square value from table.

That's why answer is:

No, the X^2 = value indicates that the observed progeny are significantly different from what would be expected with independent assortment of genes.

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