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In humans, the presence of freckles (F) is dominant to the absence of freckles (f). If...

In humans, the presence of freckles (F) is dominant to the absence of freckles (f). If two heterozygous individuals mate, what is the probability of having a child with NO freckles

a. 100%

b. 50%

c. 25%

d. 75%

0 0
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Answer #1

Here, the correct option is c) 25%

Explanation -

Here ' F ' be the dominant allele responsible for the presence of freckles and let ' f ' be the corresponding recessive allele responsible for the absence of freckles.
Now, the following are the possible genotypes and the corresponding phenotypes:
FF = Freckles present
Ff = Freckles present but heterozygous
ff = Freckles absent
The genotype of the parents = Ff and Ff
Parents: Ff X Ff Qameter : Bo @ offprings: I F If F FF I FI Jl Al 1 Aff Thus, I the of the offspring child are without freckl

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