Question

A flute can be modeled as an open-open tube. My flute is L = 0.5969 m from mouthpiece (one open end) and the end (the other open end). Assume 20 °C. a) What is the frequency of the m = 3 mode when the flute is open to atmosphere only at the two open ends? b) I lift a key that creates a hole 2V/5 from the open end. Recall that this hole opens to atmospheric pressure, as do the open ends. i. Draw the lowest-frequency mode that meets the boundary conditions at the two open ends and this new hole at 2V/5. ii. Calculate the frequency and wavelength of this mode.

Answer 1

TE20°c A flute can be modeled as an open-open tube. My flute is L = 0.5969 m from mouthpiece (one open end) and the end (the other open end). Assume 20 °C. a) What is the frequency of the m = 3 mode when the flute is open to atmosphere only at the two open ends? b) I lift a key that creates a hole 20/5 from the open end. Recall that this hole opens to atmospheric pressure, as do the open ends. i. Draw the lowest-frequency mode that meets the boundary conditions at the two open ends and this new hole at 20/5. ii. Calculate the frequency and wavelength of this mode. 0.5969m--> b) N4 => 3 = 6.5969 ** 3l/s- 2415 This will work by hit & trial method first case possible is 2 x => 2=22 » +=4L 2 s 2215 But cannot make boundary condition in 3215 past by this => d= 0.4m V= 343m's => Xf=v => f = 343 343 -857-5Hz 0.4

so xco <22IS<321s. 2215= ☺ 34=32 2 5 da 22 Both are Sanne for this is minimuin condition x0.5969 => x=0-24 m x=2 5 > I f= 343 =1429.2Hz 0 24