Calculate the power consumption from the DC power supply for our two transistor amplifier when there is no AC input signal.
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Calculate the power consumption from the DC power supply for our
two transistor amplifier when there...
IX With reference to the transistor amplifier shown in Figure QB4 below d For the bipolar transistor circuit of Figure QB4 the following DC bias conditions were measured: VB made. 1.6 V and VBE =0.6...
IX With reference to the transistor amplifier shown in Figure QB4 below d For the bipolar transistor circuit of Figure QB4 the following DC bias conditions were measured: VB made. 1.6 V and VBE =0.6 V. Detemine the value for RA, stating any assumptions e) Using these same conditions, calculate the current in Re and deduce the current in Rc, stating any assumptions made. Hence find the voltage across Rc and explain whether this voltage is suitable for this amplifier...
ee e A Quèstion 27 Calculate the minimum power rating (Po) for transistor in the loaded Common Emitter Amplifier be...
ee e A Quèstion 27 Calculate the minimum power rating (Po) for transistor in the loaded Common Emitter Amplifier below Assume Boc- BAC= 149 , Use the exact method to calculate Ip. R1 680 R, R2 510 Q Voc 16 V RL 120 5.1 Q RE2 80 Q, Rc 85 RE1 Enter your results in mW SR1 RC C3 Vcc Vout C1 HI Beta Vin RL Vs RE1 RE2 C2 R2
ee e A Quèstion 27 Calculate the minimum power...
Shown below is a single stage common emitter amplifier with a unipolar dc power supply using an 2...
Shown below is a single stage common emitter amplifier with a unipolar dc power supply using an 2N3904 NPN BJT as the active device. It is specified that V+ 40 V, C1 C2CE 100uF, Ro-7.5 k2, REi-5.1kS2, and Ri - 36k52. Design the circuit so that the dc collector current is 2 mA and the magnitude of the small-signal midband voltage gain is 32.3. For the design calculations assume that the base-to- emitter dc voltage drop is 0.65 V, the...
F LOpoint For the circuit shown in Figure 3 3. 1. Draw the DC equivalent circuit...
F LOpoint For the circuit shown in Figure 3 3. 1. Draw the DC equivalent circuit by opening caps and shorting inductors 2. Analyze the DC equivalent circuit as we have in previous labs (assume a region, analyze and check assumptions). Check your DC operating point using LT Spice. 3. Calculate the small signal parameters (transconductance, output resistance, input resistance) 4. Draw the AC equivalent circuit by shorting de voltage sources, opening dc current sources, shorting caps and opening inductors....
Blackboard X A wOVIny T0anoer queauoTWaaveUnT0aUrie Question 24 Calculate the power gain (Ap) for the loaded Common...
Blackboard X A wOVIny T0anoer queauoTWaaveUnT0aUrie Question 24 Calculate the power gain (Ap) for the loaded Common Emitter Amplifier below Assume BAC200, Assume re' 16 0 Vcc 15 V R1 66.4 KQ, R2 25.8 KO Rc 3.9 KQ RE1 3300, RE2 1.8 KO, RL 3.54 KO Enter your results. No units. SR1 RC C3 Vcc Vout Vin HH Beta RL Vs R2 RE1 RE2 C2 AMoving to another question will save this response. ww
Blackboard X A wOVIny T0anoer queauoTWaaveUnT0aUrie...
We have an amplifier that draws 2A from a 15-V dc power supply. The input signal...
We have an amplifier that draws 2A from a 15-V dc power supply. The input signal current is 1mA rms, and the input resistance is 2 k ohm. The amplifier delivers 12V rms to an 8 ohm load. Determine the power dissipated in the amplifier and the efficiency of the amplifier.
Question 26 Calculate the output power Pout (RL) for the unloaded Common Emitter Amplifier below BDC=200, BAC =...
Question 26 Calculate the output power Pout (RL) for the unloaded Common Emitter Amplifier below BDC=200, BAC = 150, re 0.39 Vs- 538 mVpp, Vcc 15 V, R1=1 KQ, R2 = 330 2 RC= 1000, RE1= 8.20, RE2= 36 0, RL 0.19 KO Enter your results in mW. SR1 RL Vcc C1 Vin Beta Vs R2 RE1 RE2 C2 ww
Question 26 Calculate the output power Pout (RL) for the unloaded Common Emitter Amplifier below BDC=200, BAC = 150, re...
pls answer all and asap.tqvm. (a) () What is the significant used of multistage amplifier compared...
pls
answer all and asap.tqvm.
(a) () What is the significant used of multistage amplifier compared to single stage amplifier? (2 marks) (ii) In terms of circuit connection, how to differentiate between direct and capacitively coupled amplifier circuit? (1 mark) (ii) Give a reason why the capacitively coupled amplifier circuit is not suitable for amplifying DC voltage? (2 marks) (b) The multistage amplifier circuit of Figure Q.3 have the following parameters: Q1, Q2: B = 200, VBE = 0.7 V,....
1.0 kn. RE-390 Ω, r-15 Ω. and ßac-75. 5. For a common-emitter amplifier, Rc Assuming that Rg is completely bypassed at the operating frequency, the voltage gain is (a) 66.7 (d) 75 (b) 2.56 (c) 2....
1.0 kn. RE-390 Ω, r-15 Ω. and ßac-75. 5. For a common-emitter amplifier, Rc Assuming that Rg is completely bypassed at the operating frequency, the voltage gain is (a) 66.7 (d) 75 (b) 2.56 (c) 2.47 6. In the circuit of Question 5, if the frequency is reduced to the point where Xctbypass) RE, the voltage gain (a) remains the same (b) is less (c) is greater 7. In a common-emitter amplifier with voltage-divider bias, Rimlbase) 68 k2, Ri 33...
Question 3. Unregulated supply Rz IL Vin IR Ib (a) The circuit on the right shows...
Question 3. Unregulated supply Rz IL Vin IR Ib (a) The circuit on the right shows a series regulator connected to the output of an unregulated power supply. The transistor has B =50, and a 6 volt Zener diode is used. When the load current, Il, is 1 amp the de input voltage from the unregulated supply, Vin, is 11 volt, VBE = 1 volt and the Zener diode current, Iz, is 20 mA. For these conditions, calculate Iz (i)...
IX With reference to the transistor amplifier shown in Figure QB4 below d For the bipolar transistor circuit of Figure QB4 the following DC bias conditions were measured: VB made. 1.6 V and VBE =0.6 V. Detemine the value for RA, stating any assumptions e) Using these same conditions, calculate the current in Re and deduce the current in Rc, stating any assumptions made. Hence find the voltage across Rc and explain whether this voltage is suitable for this amplifier...
ee e A Quèstion 27 Calculate the minimum power rating (Po) for transistor in the loaded Common Emitter Amplifier below Assume Boc- BAC= 149 , Use the exact method to calculate Ip. R1 680 R, R2 510 Q Voc 16 V RL 120 5.1 Q RE2 80 Q, Rc 85 RE1 Enter your results in mW SR1 RC C3 Vcc Vout C1 HI Beta Vin RL Vs RE1 RE2 C2 R2
ee e A Quèstion 27 Calculate the minimum power...
Shown below is a single stage common emitter amplifier with a unipolar dc power supply using an 2N3904 NPN BJT as the active device. It is specified that V+ 40 V, C1 C2CE 100uF, Ro-7.5 k2, REi-5.1kS2, and Ri - 36k52. Design the circuit so that the dc collector current is 2 mA and the magnitude of the small-signal midband voltage gain is 32.3. For the design calculations assume that the base-to- emitter dc voltage drop is 0.65 V, the...
F LOpoint For the circuit shown in Figure 3 3. 1. Draw the DC equivalent circuit by opening caps and shorting inductors 2. Analyze the DC equivalent circuit as we have in previous labs (assume a region, analyze and check assumptions). Check your DC operating point using LT Spice. 3. Calculate the small signal parameters (transconductance, output resistance, input resistance) 4. Draw the AC equivalent circuit by shorting de voltage sources, opening dc current sources, shorting caps and opening inductors....
Blackboard X A wOVIny T0anoer queauoTWaaveUnT0aUrie Question 24 Calculate the power gain (Ap) for the loaded Common Emitter Amplifier below Assume BAC200, Assume re' 16 0 Vcc 15 V R1 66.4 KQ, R2 25.8 KO Rc 3.9 KQ RE1 3300, RE2 1.8 KO, RL 3.54 KO Enter your results. No units. SR1 RC C3 Vcc Vout Vin HH Beta RL Vs R2 RE1 RE2 C2 AMoving to another question will save this response. ww
Blackboard X A wOVIny T0anoer queauoTWaaveUnT0aUrie...
Question 26 Calculate the output power Pout (RL) for the unloaded Common Emitter Amplifier below BDC=200, BAC = 150, re 0.39 Vs- 538 mVpp, Vcc 15 V, R1=1 KQ, R2 = 330 2 RC= 1000, RE1= 8.20, RE2= 36 0, RL 0.19 KO Enter your results in mW. SR1 RL Vcc C1 Vin Beta Vs R2 RE1 RE2 C2 ww
Question 26 Calculate the output power Pout (RL) for the unloaded Common Emitter Amplifier below BDC=200, BAC = 150, re...
pls
answer all and asap.tqvm.
(a) () What is the significant used of multistage amplifier compared to single stage amplifier? (2 marks) (ii) In terms of circuit connection, how to differentiate between direct and capacitively coupled amplifier circuit? (1 mark) (ii) Give a reason why the capacitively coupled amplifier circuit is not suitable for amplifying DC voltage? (2 marks) (b) The multistage amplifier circuit of Figure Q.3 have the following parameters: Q1, Q2: B = 200, VBE = 0.7 V,....
1.0 kn. RE-390 Ω, r-15 Ω. and ßac-75. 5. For a common-emitter amplifier, Rc Assuming that Rg is completely bypassed at the operating frequency, the voltage gain is (a) 66.7 (d) 75 (b) 2.56 (c) 2.47 6. In the circuit of Question 5, if the frequency is reduced to the point where Xctbypass) RE, the voltage gain (a) remains the same (b) is less (c) is greater 7. In a common-emitter amplifier with voltage-divider bias, Rimlbase) 68 k2, Ri 33...
Question 3. Unregulated supply Rz IL Vin IR Ib (a) The circuit on the right shows a series regulator connected to the output of an unregulated power supply. The transistor has B =50, and a 6 volt Zener diode is used. When the load current, Il, is 1 amp the de input voltage from the unregulated supply, Vin, is 11 volt, VBE = 1 volt and the Zener diode current, Iz, is 20 mA. For these conditions, calculate Iz (i)...
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