Question

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d) (450.60+790) / (0.6700)(5070 .)=

06. Convert 0.4890 μm to mile: 

07. Change 0.0062 lb to ng:

08. Transform 8.00 × 10° ft to fl oz: 

09. How many kerneis of popcorn are present in 0.750 pounds of popcorn if the average mass of a kernel of popcorn is 125 mg ? 

10. An unknown object with a mass of 13.75 g raises the volume of water in a graduated cylinder from 25.5 mL to 38.5 mL. What is the density of the unknown object? 

11. The density of methanol, a colorless organic liquid used as solvent is 0.7918 g / mL. Calculate the mass of 128.9 mL of the liquid. 

12. Bromine is a redish-brown liquid. Calculate the volume of 987.55 g of bromine if the density of bromine is 3.12 g/mL. 

13. Ethylene glycol, commonly used as an automobile antifreeze, has a specific gravity of 1.1088 at room temperature (25.0℃). Find the mass of 3.75 L of ethylene glycol at this temperature. 

Answer 1

While solving these questions we will make use of some basic concepts and relationships.

For calculation part we use : BODMAS rule . We will follow the sequence as Bracket, Of, Division, Multiplication, Addition and Subtraction.

1 um = 1 micro meter = 10^-6 meter

1 mile = 1.609 kilometers

1 kilometer = 1000 meter

1 lbs = 453.59 grams

1 gram = 10^9 grams

1 ft^3 = 28.32 liters

1 liter = 33.814 fl oz

For detailed solution and explanation, please refer to images as attached.

PAGE Question a) (450.60 + 790)/(0.6700)( 5070) = ? Solution:- (450.60 +790) (0-6700) (5070) using BODMAS Rule. Solving in Sequence >> Bracket, of, Division, multiplication , Nddition and subtraction Solving Bruchtete fiest * (450.60 +190) * (0.6700 (5070) => 450.60 = 0.6700 X 5070 + 7400 12 40.60 5070 x 670 $ 10bbd 507x67 10 => 507 X67 3544 304 2x 33969 => 33969 lo 33 96.4 . rebooting 33969 to u significant figurs. 33971 VHGEWS So 1240.60 (450.60 +790) (0.6700) (5070) 3397 7 0.365204 ANSWER.

PAGE 3 Question 07 Change 0.0062 16 to ny Solution: - We have О. оо 64 ГБ We know that i | 2b = 453. 54 T and lg = 109 hy where = Gram - Nanogram. So - 453 54 5 186 - 153 • 59 Хоч ng we have giveno- o, oo 63 0, So с. оо 63 b = 0. 00 69x453454x10° ng О: oo68 x453. S4 Хоч оч я ба х45 354 x| о ч 10000 X 100 ng 4 - 6 ба х Чs3 54 xo ng Адвобоѕ8 xlo3 ha 09 2 • Bo6 050 xlo 6 xio 3 9 О-ооба лh = • 8о хто na

PALE Question (68) Transform 8.00X10-3 ft 3 to fl OZ Here - |ft} t'= 28.32 Litece And I litru = 33.814 33.814 fi floz S. 8.00 X10-3 ft 8.00x10 -3 X 28,32 L 8.00 X28-32x10-3 L 꾸 226.56X10-3 L 0.29 656 L And IL = 33.814 fl OZ so 0:22 656 L= 7 7. 66 0.22656 X 33.814 floz 66f1. ft3 = 760 fl 02 So 8.00 X10-3 fl oz

PAGE-6 How Many Kernels of Popcoth are presents in 0.750 pounds, if the Average mass of a Kernel of popcorn is 125 mg? Solution - Here We know that I bound = 453.59 geram And Img = 1 milligram = 10-3 gram So my 10-3 geram So Weight of Popcorn in geams = 0.750 X 453.59 geramy = 340.195 grams. Average weight of a kernel of Popcorth = 125 mg f = 125X10-gram Number of kernels of Popcorina mars of Popcorn Average mars of Kernel of Popcorn 340.1925 gelam 125 X 10 -3 gefan 9.7.214103 2121 Kernels of popcorn are presenti