1. Scatter Diagram:
2. Line of Regression: y-hat = 29.8720 + 1.2711*x
so b0 = 29.8720 and b1= 1.2711
3. Coefficient of correlation (r) = 0.6171
4. Make a prediction:
For height(x) 75, weight will be = 29.8720 + 1.2711 * 75 = 125.2045
/******************************************* R Output *****************************************8/
survey_data<-read.csv("D:/Sourav/Chegg Question and
Answer/R_Programming/Q_1/Data.csv", header=TRUE)
> survey_data
Height_x Weight_Y
1 71 121
2 68 119
3 67 120
4 70 122
5 70 118
6 66 114
7 68 108
8 72 122
9 65 112
10 70 116
> model <- lm(survey_data$Weight_Y ~
survey_data$Height_x)
> summary(model)
Call:
lm(formula = survey_data$Weight_Y ~ survey_data$Height_x)
Residuals:
Min 1Q Median 3Q Max
-8.3102 -0.7636 0.4187 2.2364 4.9610
Coefficients:
Estimate Std. Error t value Pr(>|t|)
(Intercept) 29.8720 39.3880 0.758 0.4700
survey_data$Height_x 1.2711 0.5731 2.218 0.0573 .
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
Residual standard error: 3.891 on 8 degrees of freedom
Multiple R-squared: 0.3808, Adjusted R-squared:
0.3034
F-statistic: 4.92 on 1 and 8 DF, p-value: 0.05734
PLEASE LET ME KNOW IF YOU HAVE ANY DOUBTS. THANKS!!
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