Question

Suppose the conducting spherical shell of the figure below carries a charge of 3.50 nC and that a charge of -1.70 nC is at the center of the sphere. If a-1.60 m and b 2.30 m, find the electric field at the following. Gaussian Caussian surface surface (a) r = 1.50 m Your response differs from the correct answer by more than 10%. Double check your calculations. NC (b) r 2.20 m N/C (c) r 2.50 m. Your response differs from the correct answer by more than 10%. Double check your calculations. N/C (d) What is the charge distribution on the sphere? inner surface nc outer surface Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. nC

Answer 1

Ans:-

Given data :

q1= 3.5nC , q2= -1.7nC , a= 1.6m, b= 2.3m

E= k*q/r^2

k= 9*10^9

a] r = 1.5m

E = 9*10^9*-1.7*10^-9/1.5^2

E= 6.8N/C

B] r= 2.20m

E= 0 N/C

Charge inside the conductor is zero so electric field is zero

C]r= 2.50m

E = 9*10^9 (3.5 – 1.7 )*10^-9 /2.5^2

E = 2.59N/C

D]Charge of inner surface = 1.7*10^-9/?(1.6)^2

=2.12*10^-10C

=0.212nc

Charge of outer surface = 3.5/3.14*2.3^2 = 0.211nC