You want to find the standard deviation of the internal body temperatures of a group of healthy adults. Here are the temperatures, in degrees Fahrenheit:
99.2 98.9 98.2 97.3 98.9 98.4 97.2 99.1
Find the mean of this data set: Answer?
Now, use the mean to find the deviation for each score. The deviation is the score minus the mean.
Data Value | Deviation = Data Value - Mean |
99.2 | Answer? |
98.9 | Answer? |
98.2 | Answer? |
97.3 | Answer? |
98.9 | Answer? |
98.4 | Answer? |
97.2 | Answer? |
99.1 | Answer? |
What is the sum of all the deviations? Answer?
Mean=(99.2+ 98.9+98.2+97.3+98.9 +98.4+97.2+99.1)/8
Mean=787.2/8
mean of this data set=98.4
Data value | Deviation=Data value -mean | Deviation ^2 |
99.2 | 99.2-98.4=0.8 | 0.64 |
98.9 | 98.9-98.4=0.5 | 0.25 |
98.2 | 98.2-98.4=-0.2 | 0.04 |
97.3 | 97.3-98.4=-1.1 | 1.21 |
98.9 | 98.9-98.4=0.5 | 0.25 |
98.4 | 98.4-98.4=0 | 0 |
97.2 | 97.2-98.4=-1.2 | 1.44 |
99.1 | 99.1-98.4=0.7 | 0.49 |
Sum=0 | 4.32 |
Sum of deviation=0.8+0.5-0.2-1.1+0.5+0-1.2+0.7=0 d
Population std deviation deviation=Sqrt(sum(Data value-mean)2/n)=Sqrt(4.32/8)=0.734847
Sample deviation deviation=Sqrt(sum(Data value-mean)2/n-1) =sqrt(4.32/7)=0.7855
You want to find the standard deviation of the internal body temperatures of a group of...
Use the body temperatures, in degrees Fahrenheit listed in the accompanying table. The range of the data is 33 f Use the range rule of thumb to estimate the value of the standard deviation Compare the result to the actual standard deviation of the data founded to two decimal places, 0.74"F, assuming the goal is to approximate the standard deviation within 0.2°F. Click the icon to view the table of body temperatures The estimated standard deviation is (Round to two...
The body temperatures in degrees Fahrenheit of a sample of adults in one small town are: 98.4 97.3 96.7 96.5 97.7 98.9 99.7 98.5 Assume body temperatures of adults are normally distributed. Based on this data, find the 99% confidence interval of the mean body temperature of adults in the town. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places. Assume the data is from a normally distributed population. 99% C.I. =
Refer to the data set of body temperatures in degrees Fahrenheit given in the accompanying table and use software or a calculator to find the mean and median. Do the results support or contradict the common belief that the mean body temperature is 98.6 F? Click the icon for the body temperature data. The mean of the data set isF. Round to two decimall places as needed Body Temperatures 99.2 99.2 98.2 98.0 97.8 97.1 97.9 98.7 98.7 98.8 98.4...
The accompanying table lists body temperatures from 68 different randomly selected subjects measured at two different times in a day. Assume that the paired sample data are simple random samples and the differences have a distribution that is approximately normal. Complete parts (a) and (b) below. Click the icon to view the data on body temperatures. a. Use a 0.05 significance level to test the claim that there is no difference between body temperatures measured at 8 AM and at...
Human Body Temperatures Males Females 98.6 97.0 98.2 98.0 97.4 96.4 97.8 98.2 97.6 99.0 98.0 98.0 97.01 97.7 97.8 97.2 97.4 98.8 98.8 98.6 98.6 98.7 97.8 97.9 98.2 98.5 99.2 97.7 97.6 97.5 97.3 97.0 980 Heights of Men (in inches) Reported Measured 68 66.8 74 | 73.9 82.25 74.3 66.5 1 66.1 69 67.2 67.9 69.4 70 69.9 70 68.6 67.9 67.6 68 67 68 70 68.8 98.9 When asked, most of us will identify the mean...
The body temperatures in degrees Fahrenheit of a sample of adults in one small town are: 98.6 967 99.8 97.2 98 98.8 98 964 99.2 99.3 Assume body temperatures of adults are normally distributed. Based on this data, find the 80% confidence interval of the mean body temperature of adults in the town. Enter your answer as an open-interval (i.e., parentheses) accurate to 1 decimal place. Assume the data is from a normally distributed population. 80% CI,- Preview
the body temperatures of adults are normally distributed with a mean of 98.6 degrees Fahrenheit and a standard deviation of 0.60 degrees Fahrenheit if 36 adults are randomly selected find the probability that their mean body temperature is greater than 98.4 degrees Fahrenheit
The body temperatures in degrees Fahrenheit of a sample of adults in one small town are: 98 97.1 99.5 96.9 97.7 98.9 97.6 96.3 98.4 99 99.4 99.8 98. Assume body temperatures of adults are normally distributed. Based on this data, find the 98% confidence interval of the mean body temperature of adults in the town. Enter your answer as an open-interval (i.e., parentheses) accurate to 3 decimal places. Assume the data is from a normally distributed population. 98% C.1....
(20 points) A study is being conducted on the average human body temperature under normal conditions. The study obtained the following data in fahrenheit. Men 96.9 97.4 97.5 97.8 97.8 | 97.9 98 98.1 98.6 98.8 97.2 99.1 98.3 96.9 97.5 T T T Women 97.8 98 98.2 98.2 98.2 98. 6 98.8 | 98.8 | 99.2 99.4 98.2 97 | 97.3 98.9 97.9 99.1 (a) Treating this data as a simple random sample, estimate the average body temperature and...
The body temperatures of a group of healthy adults have a bell-shaped distribution with a mean of 98.11 degrees F and a standard deviation of 0.44 degrees F. Using the empirical rule, find each approximate percentage below. a. What is the approximate percentage of healthy adults with body temperatures within 2 standard deviations of the mean, or between 97.23 degrees F and 98.99 degrees F? b. What is the approximate percentage of healthy adults with body temperatures between 97.67 degrees...