1. Replicate GCGTTAATCGATCATGAT 2. Transcribe ATT-GCA 3. Write the anticodon for GAA? 4. Construct protein from...
1. Replicate GCGTTAATCGATCATGAT
2. Transcribe ATT-GCA
3. Write the anticodon for GAA?
4. Construct protein from UUU-AGU-AAA-CCA-CCC-AGG
5. Make mRNA transcript from Trp-Met-Asp?
Homework Answers
Answer
1) Repication of
GCGTTAATCGATCATGAT is
CGCAATTAGCTAGTACTA
2) Transcription of
ATT-GCA is
UAA-CGU
3) anticodons of GAA
is CUU
4) protein from
UUU-AGU-AAA-CCA-AGG
Phe-ser-lys-pro-arg
5) mRNA for
Trp-Met-Asp are
- UUU-AUG-GAU
-UUC-AUG-GAU
-UUU-AUG-GAC
-UUU-AUG-GAC
Add Answer to:
1. Replicate GCGTTAATCGATCATGAT
2. Transcribe ATT-GCA
3. Write the anticodon for GAA?
4. Construct protein from...
15. Transcribe into mRNA and then translate into amino acids (protein) the following DNA sequence TAC...
15. Transcribe into mRNA and then translate into amino acids (protein) the following DNA sequence TAC ATG TCT AGG ATC. Write out the tRNA anticodons for each of the 5 codons as well. What is the complementary DNA sequence for the above DNA (the complementary sequence would be produced in DNA replication)? Suggested Format: DNA: TAC ATG TCT AGG ATC. Complementary: mRNA based on DNA: TRNAs that would pair with mRNA (the anticodon): Amino Acid Sequence: To transcribe the sequence...
Bring this DNA sequence to protein using the transcription (3pts) and translation (4 pts) processes. note:...
Bring this DNA sequence to protein using the transcription
(3pts) and translation (4 pts) processes.
note: Pending the direction your DNA is located
Second position UUU Ae UCU UCC cys DU Sey UAU UAC UAA UAG UGU UGC UGA UGG UUA tyr Stop Stop JC Stop CUU CUC his CUA 5 'ATGCCGACGCCATAA 3' Lleve esta secuencia de ADN hasta proteína mediante los procesos de transcripción (3pts) y traducción (4 pts). First position (5'-end) CUC AUU AUC ile AUA AUG met...
Please answer number 21-25, explain and clearly indicate which number you are answering. Thanks in advance!...
Please answer number 21-25, explain and clearly indicate
which number you are answering. Thanks in advance!
(Q21-25) We have the following double-stranded
DNA sequences, which codes for a 10 amino acid long protein gene.
Use the codon table and answer the questions.
5'-CCTGTGTCACTCACAGGGGATGGTATCACAGTGAGTCATGGGTTT-3'
3'-GGACACAGTGAGTGTCCCCTACCATAGTGTCACTCAGTACCCAAA-5'
21. Which strand codes for this protein?
A. top
B. bottom
C. both strands
D. none of the above
22. If this is a eukaryotic gene, which RNA polymerase
will make mRNA?
A. RNA Pol I...
A template strand of DNA in a gene reads 3’ CCA AGC TCT 5’. Using the...
A template strand of DNA in a gene reads 3’ CCA AGC TCT 5’.
Using the codon chart provided, answer the following
questions:
-What is the sequence of amino acids that is produced when this
gene is translated?
-If a mutation causes a substitution (an A instead of a T) 3’
CCA AGC ACT 5’, what effect will it have on the mRNA transcript AND
on the protein?
-What do we call this type of mutation?
Second letter U С...
Repo Fill in the needed bases, codon, anticodon, or amino acid needed to complete the following...
Repo Fill in the needed bases, codon, anticodon, or amino acid needed to complete the following table that relates the sequences of DNA, mRNA, RNA, and the resulting polypeptide. DNA informational strand: 5' end 3' end Guide DNA template strand: 3' end GTC CCC GCG GGG ACG TTG 5' end mRNA codons: 5' end 5' end 0 0 3'end 3' end tRNA anticodons: Polypeptide: TABLE 22.3 The Genetic Code - Triplets in Messenger RNA First Base (5 end) Second Base...
you are informed that CGATCA codes for an intron UUU)phe UCU UAU TVE UUC) Pne UCC...
you are informed that CGATCA codes for an intron
UUU)phe UCU UAU TVE UUC) Pne UCC Ser UAC 'yr UUA UCA Ser UUG Leu UCG) UGUve UGC Cys UAA Stop UGA Stop UAG Stop UGG Trp CGU) CGC CCU CUU CUC CCC Pro CAC His CỦA Leu CCA CCG) CAAGI CGA Arg CUG) CAGS CGG First letter DOC DOC DOC Doco Third letter AAU Asn AGU Ser AGC Se AAA Lys AGA Arg AAG AGG/Arg AUU ACU AUC lle ACC...
The following genomic DNA sequence comes from the first exon of a human gene and contains...
The following genomic DNA sequence comes from the first exon of a human gene and contains the 3'-end of the 5'-untranslated region and the start of a long open reading frame that codes for 200 amino acids (a.k.a. coding sequence). Note: There are no introns in this short portion and only one strand of the genomic DNA is shown. Which of the following answers lists the first three amino acids of the translated protein correctly? Seconed Position tyr ser leu...
The next DNA sequence is the MATRICE strand of a small gene. What is the complete...
The next DNA sequence is the MATRICE strand of a small gene. What is the complete amino acid sequence of the encoded peptide? GTCATGGCAACATAG 5'-3 Standard Genetic Code First position (5'end) U Second position UAU Tyr UAC Tyr UCA Ser UAA StopUGA Stop UAG Stop UUU Phe UUC Phe UUA Leu UUG Leu UGU Cys UGC Cys UCU Ser UCC Ser UCG Ser UGG Trp CUU Leu CUC Leu CUA Leu CUG Leu CCU Pro CCC Pro CCA Pr CCG...
mRNA transcr leaves the mucl ke protcins Th eings the amino no acids anre the bui...
mRNA transcr leaves the mucl ke protcins Th eings the amino no acids anre the bui ead in onder to. start and stop mak Land when to stot C. Use your codon chart to determine the amino acid sequence. Remember to read through the strand and ONLY start on AUG and STOP when it tells you to stop Follow example below Example: DNA AGA CGG TAC CTC CGG TGG GTG CTT GTC TGT ATC CTT CTC AGT ATC UCU GCC...
You are synthesizing messenger RNAs in vitro with bases incorporated in random sequences with the ratio...
You are synthesizing messenger RNAs in vitro with bases incorporated in random sequences with the ratio of 16:3A. What is the probability of obtaining a glycine (gly) codon? second base U UAU tyr DỤC phe UUA leu UACS UAA Stop UAG Stop G UGU UGC ſys UGA Stop UGG trp CGU CGC CAU , his CÁC his CỦA / leu CAA 1. arg CGA с UUU 2 UCU UCC ser UCA UUG) UCG CUU CCU CUC CCC CCA } pro...
15. Transcribe into mRNA and then translate into amino acids (protein) the following DNA sequence TAC ATG TCT AGG ATC. Write out the tRNA anticodons for each of the 5 codons as well. What is the complementary DNA sequence for the above DNA (the complementary sequence would be produced in DNA replication)? Suggested Format: DNA: TAC ATG TCT AGG ATC. Complementary: mRNA based on DNA: TRNAs that would pair with mRNA (the anticodon): Amino Acid Sequence: To transcribe the sequence...
Bring this DNA sequence to protein using the transcription
(3pts) and translation (4 pts) processes.
note: Pending the direction your DNA is located
Second position UUU Ae UCU UCC cys DU Sey UAU UAC UAA UAG UGU UGC UGA UGG UUA tyr Stop Stop JC Stop CUU CUC his CUA 5 'ATGCCGACGCCATAA 3' Lleve esta secuencia de ADN hasta proteína mediante los procesos de transcripción (3pts) y traducción (4 pts). First position (5'-end) CUC AUU AUC ile AUA AUG met...
Please answer number 21-25, explain and clearly indicate
which number you are answering. Thanks in advance!
(Q21-25) We have the following double-stranded
DNA sequences, which codes for a 10 amino acid long protein gene.
Use the codon table and answer the questions.
5'-CCTGTGTCACTCACAGGGGATGGTATCACAGTGAGTCATGGGTTT-3'
3'-GGACACAGTGAGTGTCCCCTACCATAGTGTCACTCAGTACCCAAA-5'
21. Which strand codes for this protein?
A. top
B. bottom
C. both strands
D. none of the above
22. If this is a eukaryotic gene, which RNA polymerase
will make mRNA?
A. RNA Pol I...
A template strand of DNA in a gene reads 3’ CCA AGC TCT 5’.
Using the codon chart provided, answer the following
questions:
-What is the sequence of amino acids that is produced when this
gene is translated?
-If a mutation causes a substitution (an A instead of a T) 3’
CCA AGC ACT 5’, what effect will it have on the mRNA transcript AND
on the protein?
-What do we call this type of mutation?
Second letter U С...
Repo Fill in the needed bases, codon, anticodon, or amino acid needed to complete the following table that relates the sequences of DNA, mRNA, RNA, and the resulting polypeptide. DNA informational strand: 5' end 3' end Guide DNA template strand: 3' end GTC CCC GCG GGG ACG TTG 5' end mRNA codons: 5' end 5' end 0 0 3'end 3' end tRNA anticodons: Polypeptide: TABLE 22.3 The Genetic Code - Triplets in Messenger RNA First Base (5 end) Second Base...
you are informed that CGATCA codes for an intron
UUU)phe UCU UAU TVE UUC) Pne UCC Ser UAC 'yr UUA UCA Ser UUG Leu UCG) UGUve UGC Cys UAA Stop UGA Stop UAG Stop UGG Trp CGU) CGC CCU CUU CUC CCC Pro CAC His CỦA Leu CCA CCG) CAAGI CGA Arg CUG) CAGS CGG First letter DOC DOC DOC Doco Third letter AAU Asn AGU Ser AGC Se AAA Lys AGA Arg AAG AGG/Arg AUU ACU AUC lle ACC...
The following genomic DNA sequence comes from the first exon of a human gene and contains the 3'-end of the 5'-untranslated region and the start of a long open reading frame that codes for 200 amino acids (a.k.a. coding sequence). Note: There are no introns in this short portion and only one strand of the genomic DNA is shown. Which of the following answers lists the first three amino acids of the translated protein correctly? Seconed Position tyr ser leu...
The next DNA sequence is the MATRICE strand of a small gene. What is the complete amino acid sequence of the encoded peptide? GTCATGGCAACATAG 5'-3 Standard Genetic Code First position (5'end) U Second position UAU Tyr UAC Tyr UCA Ser UAA StopUGA Stop UAG Stop UUU Phe UUC Phe UUA Leu UUG Leu UGU Cys UGC Cys UCU Ser UCC Ser UCG Ser UGG Trp CUU Leu CUC Leu CUA Leu CUG Leu CCU Pro CCC Pro CCA Pr CCG...
mRNA transcr leaves the mucl ke protcins Th eings the amino no acids anre the bui ead in onder to. start and stop mak Land when to stot C. Use your codon chart to determine the amino acid sequence. Remember to read through the strand and ONLY start on AUG and STOP when it tells you to stop Follow example below Example: DNA AGA CGG TAC CTC CGG TGG GTG CTT GTC TGT ATC CTT CTC AGT ATC UCU GCC...
You are synthesizing messenger RNAs in vitro with bases incorporated in random sequences with the ratio of 16:3A. What is the probability of obtaining a glycine (gly) codon? second base U UAU tyr DỤC phe UUA leu UACS UAA Stop UAG Stop G UGU UGC ſys UGA Stop UGG trp CGU CGC CAU , his CÁC his CỦA / leu CAA 1. arg CGA с UUU 2 UCU UCC ser UCA UUG) UCG CUU CCU CUC CCC CCA } pro...
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