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We have three beakers in the lab: Beaker A: 10% NaCl Beaker B: 0.9 % NaCl...

We have three beakers in the lab:
Beaker A: 10% NaCl
Beaker B: 0.9 % NaCl
Beaker C: 100% H2O
The solution in Beaker A is _______________. What reaction would a red blood cell have if it
is placed in Beaker C?
a. Hypertonic/it will shrink (crenate)
b. Isotonic /it will burst (hemolysis)
c. Hypertonic / it will burst (hemolysis)
d. Isotonic/it will shrink (crenate)

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Answer #1

solution in beaker A is hypertonic to red blood cells that depends on tonicity.

option c

if RBC is placed in beaker C the water will move inside the cell and it will bust

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