A chi-square test was conducted to see if a person’s drink preferences are independent of their...
A chi-square test was conducted to see if a person’s drink preferences are independent of their age group using data below.
Coffee Softdrink Other
21-34 26 95 18
35-55 41 40 20
above 55 24 13 32
4i) What is d.f. to conduct test of independence?
4i) What is the critical value?
4.iii) Given chi-square test statistic is 59.405, you can
conclude:
(a) A person’s drink preference is independent of their age
(b) A person’s drink preference is dependent on their age
(c) Independence cannot be determined since age is a quantitative variable
(d) The ‘other’ category could include Pepsi and I prefer Coke
Homework Answers
Add Answer to:
A chi-square test was conducted to see if a person’s drink
preferences are independent of their...
A Chi-square goodness-of-fit test was conducted on voter preferences in a state primary (with candidates A,...
A Chi-square goodness-of-fit test was conducted on voter preferences in a state primary (with candidates A, B, C, and D) that yielded a calculated/obtained statistic of 7.82. If you used a critical value of 6.22 to determine if the voters significantly preferred one candidate over another, what conclusion would you draw? Voters showed no significant preference Voters showed a significant preference Voters showed a significant preference for candidate A over the others Not enough information is given to be able...
11. Effect size for the chi-square test for independence Aa Aa Which of the following statements...
11. Effect size for the chi-square test for independence Aa Aa Which of the following statements are correct about the phi-coefficient? Check all that apply. It is determined only by the proportions in a 2 x 2 data matrix. It is the same as Cramer's V when the data are a 2 x 2 matrix. It can be used as a measure of the significance of a relationship between two dichotomous variables. * It can be used as a measure...
The chi-square test for homogeneity. In a study of the snack preferences of children, a marketing...
The chi-square test for homogeneity. In a study of the snack preferences of children, a marketing firm selects a random sample of 90 children under 8, 150 children aged 8-10,55 kids aged 11-13 and 50 kids aged 14-17. Each individual is asked which of the following snacks they prefer: Doritos, Ruffles, or Cheetos. Results are shown in the contingency table below. Total Snack Preferences Ruffles Doritos Cheetos 40 30 20 90 60 40 150 Under 8 Age 8-10 Age 11-13...
Effect size for the chi-square test for independence 1.Which of the following statements are correct about the phi-coefficient? Check all that apply. a.It can be used as a measure of the significance...
Effect size for the chi-square test for independence 1.Which of the following statements are correct about the phi-coefficient? Check all that apply. a.It can be used as a measure of the significance of a relationship between two dichotomous variables. b.It is the same as Cramer’s V when the data are a 2 x 2 matrix. c.It can be used as a measure of the strength of a relationship between two dichotomous variables. d.It can be used as a measure of...
(1 point) A chi-square independence test is to be conducted to decide whether an association exists...
(1 point) A chi-square independence test is to be conducted to decide whether an association exists between two variables of a populations. One variable has 6 possible values and the other variable has 8. What are the degrees of freedom for the x2-statistic? answer:
(1 point) A chi-square independence test is to be conducted to decide whether an association exists...
(1 point) A chi-square independence test is to be conducted to decide whether an association exists between two variables of a populations. One variable has 10 possible values and the other variable has 10. What are the degrees of freedom for the y2-statistic? answer:
(1 point) A chi-square independence test is to be conducted to decide whether an association exists between two var...
(1 point) A chi-square independence test is to be conducted to decide whether an association exists between two variables of a populations. One variable has 9 possible values and the other variable has 4. What are the degrees of freedom for the x-statistic? answer:
Calculate the test statistic. Chapter 12. Chi-Square Test Saved Help Save & Exit Su Check my...
Calculate the test
statistic.
Chapter 12. Chi-Square Test Saved Help Save & Exit Su Check my w Given the following contingency table, conduct a test for Independence at the 5% significance level. (You may find It useful to reference the appropriate table: chi-square table or F table) Variable A points Variable B 36 35 31 51 eBook a. Choose the null and alternative hypotheses. Hint Ho: The two variables are independent.; HA: The two variables are dependent. O Ho: The...
Please note that for all problems in this course, the standard cut-off (alpha) for a test...
Please note that for all problems in this course, the standard cut-off (alpha) for a test of significance will be .05, and you always report the exact power unless SPSS output states p=.000 (you’d report p<.001). Also, remember when hand-calculating, always use TWO decimal places so that deductions in grading won’t be due to rounding differences. Problem Set 2: Chi Square Test of Independence A public opinion poll surveyed a sample of 100 volunteers. Respondents were classified by gender (male...
Perform a chi-square homogeneity test. An independent simple random sample of residents in three regions gave...
Perform a chi-square homogeneity test. An independent simple random sample of residents in three regions gave the data on race shown in the table. At the 1% signifcance level, do the data provide sufficient evidence to conclude that a difference exists in race distributions among the three regions? White Black Other Total 91 Midwest West East 14 114 117 16 10 143 115 16 139 Total 396 323 38 35 What are the null and alternative hypotheses? OA H: The...
11. Effect size for the chi-square test for independence Aa Aa Which of the following statements are correct about the phi-coefficient? Check all that apply. It is determined only by the proportions in a 2 x 2 data matrix. It is the same as Cramer's V when the data are a 2 x 2 matrix. It can be used as a measure of the significance of a relationship between two dichotomous variables. * It can be used as a measure...
The chi-square test for homogeneity. In a study of the snack preferences of children, a marketing firm selects a random sample of 90 children under 8, 150 children aged 8-10,55 kids aged 11-13 and 50 kids aged 14-17. Each individual is asked which of the following snacks they prefer: Doritos, Ruffles, or Cheetos. Results are shown in the contingency table below. Total Snack Preferences Ruffles Doritos Cheetos 40 30 20 90 60 40 150 Under 8 Age 8-10 Age 11-13...
(1 point) A chi-square independence test is to be conducted to decide whether an association exists between two variables of a populations. One variable has 6 possible values and the other variable has 8. What are the degrees of freedom for the x2-statistic? answer:
(1 point) A chi-square independence test is to be conducted to decide whether an association exists between two variables of a populations. One variable has 10 possible values and the other variable has 10. What are the degrees of freedom for the y2-statistic? answer:
(1 point) A chi-square independence test is to be conducted to decide whether an association exists between two variables of a populations. One variable has 9 possible values and the other variable has 4. What are the degrees of freedom for the x-statistic? answer:
Calculate the test
statistic.
Chapter 12. Chi-Square Test Saved Help Save & Exit Su Check my w Given the following contingency table, conduct a test for Independence at the 5% significance level. (You may find It useful to reference the appropriate table: chi-square table or F table) Variable A points Variable B 36 35 31 51 eBook a. Choose the null and alternative hypotheses. Hint Ho: The two variables are independent.; HA: The two variables are dependent. O Ho: The...
Perform a chi-square homogeneity test. An independent simple random sample of residents in three regions gave the data on race shown in the table. At the 1% signifcance level, do the data provide sufficient evidence to conclude that a difference exists in race distributions among the three regions? White Black Other Total 91 Midwest West East 14 114 117 16 10 143 115 16 139 Total 396 323 38 35 What are the null and alternative hypotheses? OA H: The...
Most questions answered within 3 hours.
-
In a survey of 1147 small-business owners, the following
question was posed: Would you recommend working...
asked 19 minutes ago -
The value of the equilibrium constant Kc for the reaction
N2(g)+3H2(g)⇌2NH3(g) changes in the following manner...
asked 26 minutes ago -
There are two flasks on the bench top, one flask contains a 0.50
M NaCl solution...
asked 32 minutes ago -
Which of the following aqueous solutions are good buffer
systems?
.
0.10 M hydrofluoric acid +...
asked 33 minutes ago -
2. An S election is terminated if the S corporation has passive
investment income in excess...
asked 35 minutes ago -
Part of an ANOVA table is shown below.
Source of
Variation
Sum of
Squares
Degrees of...
asked 52 minutes ago -
Business process improvement initiatives often include
introducing new technology to support the new or changed ways...
asked 58 minutes ago -
Review your choice of either Agile or the Waterfall models and
for each of the 22...
asked 59 minutes ago -
Suppose an x distribution has mean μ = 4.
Consider two corresponding
x
distributions, the first...
asked 1 hour ago -
A study of the effects of exercise used rats bred to have high
or low capacity...
asked 1 hour ago -
Using your data from the experiment, calculate the initial moles
of HCl that you started with....
asked 1 hour ago -
Suppose you want to make 500 mL of a 0.20 M Tris buffer at pH
8.0....
asked 1 hour ago