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This requires the preparation of a 100 ppm Fe standard in a 500 mL standard flask....

This requires the preparation of a 100 ppm Fe standard in a 500 mL standard flask. The iron will be from a ferrous ammonium sulfate hexahydrate salt which has the formula Fe(NH4)2(SO4)2.6H2O with a molar mass of 392.14 g mol-1. If the atomic mass of Fe is 55.84 g mol-1, what mass of salt is needed?

What steps do i need to take for this?

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Answer #1

100 ppm=100mg/L or 50 mg in 500 mL solution.

50 mg De solution needed.

55.84 g Fe is in 392.14 g salt

0.05 g Fe is in (392.14×0.05)/55.84=0.35 g salt needed.

Weigh 0.35 g salt and dissolve in 500 mL solvent to prepare 100 ppm Fe solution.

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