How do you prepare 500 mL of 250 mM Tris base? (The molecular weight of Tris...

Question

Question

How do you prepare 500 mL of 250 mM Tris base? (The molecular weight of Tris base is 121.14 g/mol)

Answer 1

Answer #1

Molarity = Moles/volume of solution in liter

Moles = given mass/ molar mass

Mass of tried base required = 0.125 × 121.14 = 15.1425 g

Therefore to prepare 250 mM of 500 ml of Tried base solution, we mix 15.425 g of tried base in 500 ml of solution

Feel free to comment if you have any problem in understanding this answer.

Answer 2

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