Both Biuret and Bradford methods was used to determine unknown concentrations of both BSA and BIg.
The methods followed is described in detail in the Background section.
The following results was obtained:
Table 1: Absorbance at 595nm obtained for different concentrations of protein standards using the Bradford method
[Protein] (mg/ml) |
0.00 |
0.125 |
0.25 |
0.50 |
0.75 |
1.00 |
1.50 |
2.00 |
Unknown |
Abs. BSA |
0 |
0.130 |
0.350 |
0.620 |
0.870 |
1.120 |
1.400 |
1.60 |
1.050 |
Abs. BIg |
0 |
0.080 |
0.130 |
0.360 |
0.520 |
0.650 |
0.850 |
1.080 |
Table 2: Absorbance at 540nm obtained for different concentrations of protein standards using the Biuret method
[Protein] (mg/ml) |
0.00 |
0.125 |
0.25 |
0.50 |
0.75 |
1.00 |
1.50 |
2.00 |
Unknown |
Abs. BSA |
0 |
0.026 |
0.045 |
0.075 |
0.111 |
0.128 |
0.172 |
0.218 |
0.26 |
Abs. BIg |
0 |
0.024 |
0.052 |
0.092 |
0.136 |
0.162 |
0.223 |
0.264 |
Which standard curve would you use to determine the concentration of the Unknown protein sample?
BIg standard curve using the Bradford method |
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BIg standard curve using the Biuret method |
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BSA standard curve using the Biuret method |
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BSA standard curve using the Bradford method |
1) Blg standard curve via biuret method
BSA Standard Curve using bradford method
2) 0.625 mg/ml protein is present in unknown sample
3) Average molecular wt of protein sample- 5782 g/mole or 5782 Dalton or 5.782 kDa
1 mole= 5782 gm
1 milimol = 5.78 gm or 5780 mg
therefore,
5780 mg= 1mM
4.4 mg = (1*4.4)/5780 = 0.000760 mM
or 7.6*10-4 mmol
Both Biuret and Bradford methods was used to determine unknown concentrations of both BSA and BIg....
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0.679A
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