Question

1) Suppose you added 100 mL of water to your vinegar sample in the Erlenmeyer flask...

1) Suppose you added 100 mL of water to your vinegar sample in the Erlenmeyer flask instead of 50 mL. Would the titration have required more, less or the same amount of NaOH for a complete reaction? Explain.

2)You used a 10.00 mL volumetric pipet to dispense the vinegar sample. Can you use a cylinder instead if it has the same precision?

0 0
Add a comment Improve this question Transcribed image text
Request Professional Answer

Request Answer!

We need at least 10 more requests to produce the answer.

0 / 10 have requested this problem solution

The more requests, the faster the answer.

Request! (Login Required)


All students who have requested the answer will be notified once they are available.
Know the answer?
Add Answer to:
1) Suppose you added 100 mL of water to your vinegar sample in the Erlenmeyer flask...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Similar Homework Help Questions
  • You diluted a 12.96 ml vinegar sample into a 100 ml volumetric flask with distilled water....

    You diluted a 12.96 ml vinegar sample into a 100 ml volumetric flask with distilled water. You titrated a 25.00 mL aliquot of that solution and determined the concentration of acetic acid to 0.048 M. What was the concentration of acetic in the original sample.

  • I need it right now, please help me?? PROCEDURE PART I: DILUTING THE VINEGAR SOLUTION The...

    I need it right now, please help me?? PROCEDURE PART I: DILUTING THE VINEGAR SOLUTION The vinegar solution must be diluted by a factor of 5 to be suitable for titration. 1. Obtain - 20 ml of the stock vinegar solution from the fume hood. 2. Using the 10-ml. pipet, pipet" 10 mL of the stock solution to a 50-ml volumetric flask. 3. Fill the volumetric flask to the calibration line with distilled water. Be sure not to go over...

  • A sample of KHP weighing 0.503 grams was placed in an Erlenmeyer flask and 100 m distilled water was added to disso...

    A sample of KHP weighing 0.503 grams was placed in an Erlenmeyer flask and 100 m distilled water was added to dissolve the acid. Two drops phenolphthalein were added and a light pink endpoint was observed after the addition of 27.3 ml NaOH. What is the Molarity of the NaOH solution? Select one: O a. 0.09 M O b. 0.06 M O C. 0.07 M O d. 0.02 M

  • Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol....

    Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 ml water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the exact number of moles of KHP that will react with...

  • Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol....

    Materials: NaOH MW = 40 g/mL, KHP - potassium hydrogen phthalate, KHC8H404, MW = 204.23 g/mol. Acetic acid, HC2H302, MW = 60.05 g/mol Part 1: Standardization of NaOH Assume 0.951 g of KHP is weighed and transferred to a 250 mL Erlenmeyer flask. Approximately 50 ml water is added to dissolve the KHP. Note that the exact volume of water is not important because you only need to know the exact number of moles of KHP that will react with...

  • Assume that a 50.00 mL sample of 0.1000 M HCl in an Erlenmeyer flask is titrated...

    Assume that a 50.00 mL sample of 0.1000 M HCl in an Erlenmeyer flask is titrated with 0.1000 M NaOH. (a) What is the initial pH before any base is added? (6) What is the pH of the solution after 10.00 mL of NaOH? (c) What is the pH of the solution after 20.00 mL of NaOH? (d) What is the pH of the solution after 50.00 mL of NaOH? (e) What is the pH of the solution after 60.00...

  • Concentration of NaOH = 1600 x10- Molar Sodium hydroxide Nach Trial 1 Trial 2 Trial Trial 4 2.60/1.20 1...

    Concentration of NaOH = 1600 x10- Molar Sodium hydroxide Nach Trial 1 Trial 2 Trial Trial 4 2.60/1.20 11.40/1.30 28.20 29.10.26.1026.50 Initial buret reading Final buret reading Volume of NaOH added Moles of NaOH added Moles of HCl reacted Molarity of diluted HCI Molarity of undiluted HCI Average molarity of undiluted HCI Precision PROCEDURE 1. Obtain approximately 40 mL of an unknown acid in an Erlenmeyer flask from your teaching assistant. 2. Clean your 250-ml volumetric flask (contains exactly 250.00...

  • Concentration of NaOH = 1600 x10- Molar Sodium hydroxide Nach Trial 1 Trial 2 Trial Trial...

    Concentration of NaOH = 1600 x10- Molar Sodium hydroxide Nach Trial 1 Trial 2 Trial Trial 4 2.60/1.20 1.40/1.30 28.20 29.10.26.1026.50 Volume of NaOH added Initial buret reading Final buret reading Moles of NaOH added Moles of HCl reacted Molarity of diluted HCI Molarity of undiluted HCI Average molarity of undiluted HCI Precision PROCEDURE 1. Obtain approximately 40 mL of an unknown acid in an Erlenmeyer flask from your teaching assistant. 2. Clean your 250-ml volumetric flask (contains exactly 250.00...

  • chem 110 experiment 12 tritation vinegar need help fast please!!! The density of vinegar is 1.01...

    chem 110 experiment 12 tritation vinegar need help fast please!!! The density of vinegar is 1.01 g/mL. How would this information affect your experimental results. 2. Weak acids, such as acetic acid, typically have an odor, whereas strong acids often do not. Explain this is so EXPERIMENT # 1 2 ACETIC ACID CONTENT OF VINEGAR Objectives Use chemical pll indicators to find endpoints of acid base titrations Use the burets to undertake chemical titrations PreLab questions i. Lab. If commercial...

  • Prelab Activity: Titrations Continued – Titration of Household Products A 2.40 g sample of vinegar was...

    Prelab Activity: Titrations Continued – Titration of Household Products A 2.40 g sample of vinegar was added to an Erlenmeyer flask along with 100 mL of deionized water and 3 drops of phenolphthalein indicator. It took 22.15 mL of 0.0981 M NaOH (aq) to reach the faint pink endpoint. The following balanced chemical equation represents the chemistry of the titration: NaOH (aq) + CH3COOH (aq) à CH3COO–Na+ (aq) + H2O (l) Calculate the mass % of acetic acid (CH3COOH) in...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT