Homework Answers
Answer:
Based on the given data:
- Concentration of both Linker A and Linker B is 1 ug/ul in TE Buffer
- Conversion factor: 1ug = 1000 ng
- Therefore, Concentration of both Linker A and Linker B = 1 ug/ul in TE Buffer = 1000 ng/ul in TE Buffer
- Concentration of linker required for experiment = 20 ng/ul
- Fold dilution = Initial Concentration / Final Concentration = 1000 / 20 = 50x
- Dilute the stock concentration 50 fold to get the desired concentration.
- For this add 1ul of 1ug/ul stock of Linker A + 49ul of TE buffer to get total 50ul of diluted Linker A Sample
- Separately add 1ul of 1ug/ul stock of Linker B + 49ul of TE buffer to get total 50ul of diluted Linker B Sample
- Final concentration of linker A obtained = 1000/50 = 20ng/ul
- Final concentration of linker B obtained = 1000/50 = 20ng/ul
Add Answer to:
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microgram/microliter DNA stock, and enzyme at 10
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Question: What is the most concentrated stock of buffer A you can make? Now if you want to prepare an enzymatic reaction containing 1X buffer A, 100 ng/ul DNA stock and 1 Unit/ul (U/ul) of enzyme proceed...
Prepare the buffer. In this lab we store our buffer at a concentration 20 times the concentration used in the experiment. Thus we call it 20xLB. Before we can use it, it needs to be diluted to a 1x concentration. If we needed 20 mL of the media, we would take 1 mL of the 20xLB buffer and diluted it with 19 mL of Dl water. To make enough buffer for this experiment, we need 50 mL for the gel...
How are we getting the volumes in this solution for example
for 10Xs buffer how did we get 1 microliter please explain for each
reagent how the microliters were obtained; ddH20, 10X buffer A, 1
microgram/microliter DNA stock, and enzyme at 10
U/microliter.
Question: What is the most concentrated stock of buffer A you can make? Now if you want to prepare an enzymatic reaction containing 1X buffer A, 100 ng/ul DNA stock and 1 Unit/ul (U/ul) of enzyme proceed...
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Based on the calculations from your experimental results, is
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