Use the following information to answer questions.
A new screening test for Lyme Disease is being evaluated. It was administered to 1,235 people in southern Maine. While 115 people with the disease tested positive for it another 47 people who do not have disease tested positive for Lyme. 721 people who did not have Lyme tested negative. [Data are fictitious but realistic.]
Using the data above, complete a 2x2 table:
SOL)
According to data the following table can be written as
Test positive |
Test negative |
Total |
|
Have disease |
115 |
352 |
467 |
Not have disease |
47 |
721 |
768 |
Total |
162 |
1073 |
1235 |
We have to find test positive given have disease and test negative given not have disease
Sensitivity=P( Test positivity given have disease) |
=115/467
=0.2463
Sensitivity=P(test negative given not have disease) |
=721/768
=0.9388
Positive predictive value= true positive/total positive |
=115/162
=0.7099
We know negative predicted value=721/1073 =0.6719 |
Consequently, we should N't recommend this screening Evaluation as the text has a sensitivity That result would N't receive the Therapy and in the Majority of the Individuals with Disorder goes undetected
Use the following information to answer questions. A new screening test for Lyme Disease is being...
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