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You have purified a sample of your protein of interest and have measured the A280 of a 1 in 3 dilution of the protein sample (1 cm pathlength). The value you have obtained for A280 was 0.576. Given th...

You have purified a sample of your protein of interest and have measured the A280 of a 1 in 3 dilution of the protein sample (1 cm pathlength). The value you have obtained for A280 was 0.576. Given that you do not know the sequence of your protein, calculate the approximate concentration of your original protein sample in mg/mL. Give your answer to 2 s.f.

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Answer #1

As a reference, a protein solution of concentration 1mg/ml produces an absorbance of 1 unit at 280nm.

Hence the conecntration of protein with absorbance (A280), of 0.576 = 1 X 0.576 = 0.576mg/ml

Since the sample is diluted in 1:3 ratio.

Therefore, the concentration of undiluted sample will be, 0.576 X 3 = 1.728mg/ml

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