Question

b. Place the components and wire up the circuit shown in Figure 1. The "digital constant" input represent inputs A, and the output signal at PR1 represents the output F Note: the current that can be supplied by small transistors is fairly low. Therefore, the op amp (U1) is added to "buffer" the output signal. It does not affect the operation of the circuit. V1 02 100um 00um U1 PR1 Outofdote d Lo DG1 92 LED1 00um 00um Figure 1 Set the simulation mode to "Interactive". Simulate the circuit complete the truth table below. Enter a '0' or '1' for each of the eight output values listed). c. 0 o 33v 100m 100pm 100pm 01 100pm 03 00pm Figure 2 d. Connect the circuit shown in Figure 2. (Which logic gate does this implement?) Set the simulation mode to "Interactive", simulate the circuit, and complete the truth table below. A- DG1, BDG2, F '0' or '1' for each of the eight output values listed). PR1. (Enter a E8 0 0 0 0 0 0

Answer 1

Q. C

Q1 - PMOS   OFF when gate input is HIGH

                      ON when gate input is LOW

Q2 - NMOS   ON when gate input is HIGH

                       OFF when gate input is LOW

For input A is ONE Q2 is ON, Q1 is OFF, through Q2 VSS is connected to LED. LED is ON

For input A is ZERO Q1 is ON, Q2 is OFF, through Q1 GND is connected to LED. LED is OFF

The entire circuit is acts like a Buffer.

therefore

1) 1

2) 0

Q. D

By doing the same analysis

3) 0

4) 1

5) 1

6) 1

the entire circuit act as OR gate.