Question

18.11 A steel ring with an outside diameter of 150 mm and an inside diameter of 100 mm is shrunk onto another steel ring with an inside diameter of 50 mm. An axial force of 56,54 kN is needed to push the rings apart. Calculate the pressure at the mating surface and the shrinkage allowance given that both rings are 20 mm thick and the coefficient of friction between the mating surfaces is 0,2. Using this pressure, calculate the magnitude of the hoop stress in both rings at the inside and outside. E 200 GPa [45 MPa; 0,096 mm (diameter); 72 MPa (T; 117 MPa (T); 75 MPa (C) 120 MPa (C)] 18.12 A compound cylinder is made by forcing a gun metal cylinder having an outside diameter of 150 mm and an inside diameter of 99,925 mm onto a 100,000 mm outside diameter steel cylinder. If the inside diameter of the steel cylinder is 50 mm, calculate: (a) the contact pressure set up at the mating surface; and (b) the resultant maximum hoop stress set up in each cylinder.

please answer 18.11 and 18.12

Answer 1

5654 시03 2 ,2

0.096 mm Caiulate zhe op sthck ineutiu ring al irsids ans Outsidlo cuttr nnun 2 S02-12 117 MPa (T) h-inn

(Iv ) Calputae th heop stres in msd gring at inna ded 2. h-innn. A-in-2P de db di 2- /o02 502 a Innin