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Sapling Learning this question has been customized by Ma Joy Heising at Massachusetts College of Pharmacy & Health scie At 1
Step 1 Heat,- m AT SH- (75.0 g 2.0872.C)-3760 J Map Heat,-m A7.0 g) 333.6 J/g)-2.50x 10 J Heat,- m AT SH-(75.0 g 4.184 100 c
Sapling Learning this question has been customized by Ma Joy Heising at Massachusetts College of Pharmacy & Health scie At 1 atm, how much energy is required to heat 75.0 g of H2O(s) at-24.0 ℃ to H2O(g) at 157.0-C? STRATEGY 1. Calculate the energy for each temperature change or phase change individually a. the energy needed to heat 75.0 g of H20(s) from-24.0 C to its melting point. b. the energy needed to melt 75.0 g of H20(s) at its melting point. c. the energy needed to heat 75.0 g of H20() from the melting point to the boiling point. d. the energy needed to boil 75.0 g of H20() at its boiling point. e, the energy needed to heat 75.0 g of H2O(g) from the boiling point to 1570°C. 2. Sum the energies from each step and convert to kilojoules. Step 1: g-cl 24.0 !(24.0 g)|2.087 g o c °C)-3760 °C)-3760 J Heat.-m-&T. SH= (75.0 ΔΤ. SH. 75.0 g) 2.087 a Heah" m . Δ Hrasu" (75.0 g) (333.6 J / g)-2.50-104 J °C)-31400 J -o cl (100 Heat.-m. ΔΤ. SH-(75.0 g)|4.184 Heat,-m AHrtion (75.0 g) 2257 J/g)-169000J °C) |(57.0 8550 J g)|2.000 (75.0 Heat.-m. ΔΤ. SH
Step 1 Heat,- m AT SH- (75.0 g 2.0872.C)-3760 J Map Heat,-m A7.0 g) 333.6 J/g)-2.50x 10' J Heat,- m AT SH-(75.0 g 4.184 100 c)-31400 J g. o C Heat,-m . Δ Hvaporization-(75.0 g) (2257 J / g)-169000 J (75.0 g)|2.000 g 2.000 Heat,-m.ΔΤ-SH Step 2: What is the sum of the individual energies? Convert the sum from joules to kilojoules. Number Number kJ
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Answer #1

Sum of individual energies in J = 237710

Sum of individual energies in kJ = 237.71

The nesey sepuised to heal 7so of hodo renhofenese e-given s steps.bo to 5 50 22824 0 3Thank you.

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